In: Statistics and Probability
A basketball coach wanted to see if there was a relationship between a team and their training methods. 50 players were asked "Do you think practicing 5 times per week will help you win more games?" Below are each teams responses.
Null hypothesis: A team and their training methods are independent.
Alternative hypothesis: A team and their training methods are dependent.
Perform hypothesis testing using the Chi-Square Test for Independence and interpret the results.
| Team | 
 Strongly Agree  | 
 Agree  | 
 Neutral  | 
 Disagree  | 
 Strongly Disagree  | 
 Row Total  | 
| 
 A  | 
 1  | 
 10  | 
 2  | 
 1  | 
 0  | 
 14  | 
| B | 
 7  | 
 6  | 
 6  | 
 0  | 
 0  | 
 19  | 
| 
 C  | 
 1  | 
 3  | 
 4  | 
 0  | 
 1  | 
 9  | 
| 
 D  | 
 0  | 
 1  | 
 0  | 
 0  | 
 0  | 
 1  | 
| 
 E  | 
 1  | 
 0  | 
 4  | 
 1  | 
 0  | 
 6  | 
| 
 F  | 
 0  | 
 1  | 
 0  | 
 0  | 
 0  | 
 1  | 
| 
 Column Total  | 
 10  | 
 21  | 
 16  | 
 2  | 
 1  | 
 50  | 
Using excel<data<megastat<chi square<contigency
| Chi-square Contingency Table Test for Independence | ||||||||
| Strongly Agree | Agree | Neutral | Disagree | Strongly Disagree | Total | |||
| A | Observed | 1 | 10 | 2 | 1 | 0 | 14 | |
| Expected | 2.80 | 5.88 | 4.48 | 0.56 | 0.28 | 14.00 | ||
| O - E | -1.80 | 4.12 | -2.48 | 0.44 | -0.28 | 0.00 | ||
| (O - E)² / E | 1.16 | 2.89 | 1.37 | 0.35 | 0.28 | 6.04 | ||
| B | Observed | 7 | 6 | 6 | 0 | 0 | 19 | |
| Expected | 3.80 | 7.98 | 6.08 | 0.76 | 0.38 | 19.00 | ||
| O - E | 3.20 | -1.98 | -0.08 | -0.76 | -0.38 | 0.00 | ||
| (O - E)² / E | 2.69 | 0.49 | 0.00 | 0.76 | 0.38 | 4.33 | ||
| C | Observed | 1 | 3 | 4 | 0 | 1 | 9 | |
| Expected | 1.80 | 3.78 | 2.88 | 0.36 | 0.18 | 9.00 | ||
| O - E | -0.80 | -0.78 | 1.12 | -0.36 | 0.82 | 0.00 | ||
| (O - E)² / E | 0.36 | 0.16 | 0.44 | 0.36 | 3.74 | 5.05 | ||
| D | Observed | 0 | 1 | 0 | 0 | 0 | 1 | |
| Expected | 0.20 | 0.42 | 0.32 | 0.04 | 0.02 | 1.00 | ||
| O - E | -0.20 | 0.58 | -0.32 | -0.04 | -0.02 | 0.00 | ||
| (O - E)² / E | 0.20 | 0.80 | 0.32 | 0.04 | 0.02 | 1.38 | ||
| E | Observed | 1 | 0 | 4 | 1 | 0 | 6 | |
| Expected | 1.20 | 2.52 | 1.92 | 0.24 | 0.12 | 6.00 | ||
| O - E | -0.20 | -2.52 | 2.08 | 0.76 | -0.12 | 0.00 | ||
| (O - E)² / E | 0.03 | 2.52 | 2.25 | 2.41 | 0.12 | 7.33 | ||
| F | Observed | 0 | 1 | 0 | 0 | 0 | 1 | |
| Expected | 0.20 | 0.42 | 0.32 | 0.04 | 0.02 | 1.00 | ||
| O - E | -0.20 | 0.58 | -0.32 | -0.04 | -0.02 | 0.00 | ||
| (O - E)² / E | 0.20 | 0.80 | 0.32 | 0.04 | 0.02 | 1.38 | ||
| Total | Observed | 10 | 21 | 16 | 2 | 1 | 50 | |
| Expected | 10.00 | 21.00 | 16.00 | 2.00 | 1.00 | 50.00 | ||
| O - E | 0.00 | 0.00 | 0.00 | 0.00 | 0.00 | 0.00 | ||
| (O - E)² / E | 4.64 | 7.66 | 4.70 | 3.95 | 4.56 | 25.51 | ||
| 25.51 | chi-square | |||||||
| 20 | df | |||||||
| .1825 | p-value | 
Answer:
Since P value= 0.1825
Let us assume the level of significance =0.05
Since p value>alpha(0.05). We fail to reject the null hypothesis.
There is mot sufficient evidence to conclude that a team and their training methods are dependent.