In: Accounting
6. For each of the following situations involving single amounts, solve for the unknown. Assume that interest is compounded annually. (i = interest rate, and n = number of years) (FV of $1, PV of $1, FVA of $1, PVA of $1, FVAD of $1 and PVAD of $1) (Use appropriate factor(s) from the tables provided. Round your final answers to nearest whole dollar amount.)
Present Value Future Value
i n
1. ? $76,000 11.0% 7
2. $26,933 $90,000 ? 14
3. $17,670 $49,000 12.0% ?
4. $39,710 $190,000 ? 15
5. $24,439 ? 11.0% 12
pv | fv | i | n | |
1 | 36606 | 76000 | 11 | 7 |
2 | 26933 | 90000 | 9 | 14 |
3 | 17670 | 49000 | 12 | 9 |
4 | 39710 | 190000 | 11 | 15 |
5 | 24439 | 85499 | 11 | 12 |
1
pv of 1$ | 0.481658 |
fv | 76000 |
pv | 76000*0.481658 |
pv of 76000 | 36606 |
2
PV | = | FV*[Pvfactor for n years and I interest) | |
26933 | = | 90000 for n= 14 and I = ? | |
26933/90000 | = | pv factor for n = 14 years and I = ? | |
0.299256 | = | pv factor for n = 14 years and I = ? | |
closest to pv factor for i=9% |
3
PV | = | FV*[Pvfactor for n years and I interest) |
17670 | = | 49000*(pv factory for n=?, I =12) |
0.360612 | = | (pv factory for n=?, I =12) |
closest to pv factor for n = 9 |
4
PV | = | FV*[Pvfactor for n years and I interest) |
39710 | = | 190000*(pv factory for n=15, I =? |
0.209 | = | (pv factory for n=15, I =?) |
closest to pv factor for i= 11% |
5
FV of 1$ | 3.49845 |
PV | 24439 |
FV | 24439*3.49845 |
FV of 76000 | 85499 |
HOPE THIS WAS HELPFUL. A LOT OF EFFORTS HAVE BEEN PUT INTO THIS TO MAKE IT EASILY UNDERSTANDABLE. |
INCASE OF DOUBTS GET BACK TO ME. |
DO CONSIDER GIVING THIS A THUMBS UP. |