Question

In: Finance

Solve for the unknown number of years in each of the following

Solve for the unknown number of years in each of the following (Do not round intermediate calculations and round your answers to 2 decimal places, e.g., 32.16.)

Present ValueYearsInterest RateFuture Value
$560
7%$1,389
810
8
1,821
18,400
9
289,715
21,500
11
430,258


Solutions

Expert Solution

Future Value:

Future Value is Value of current asset at future date grown at given int rate or growth rate.

FV = PV (1+r)^n
Where r is Int rate per period
n - No. of periods

Part A:

Particulars Amount
Present Value $         560.00
Future Value $      1,389.00
Int Rate per period 7.0000%

Future Value = Cash Flow * ( 1 + r )^n
$ 1389 = $ 560 ( 1 + 0.07 ) ^ n
( 1 + 0.07 ) ^ n = $ 1389 / $ 560
1.07 ^ n = 2.4804
Take Log on Both sides
Log ( 1.07 ^ n ) = Log ( 2.4804 )
Log ( a^b ) = b * Log (a)
n * Log ( 1.07 ) = Log ( 2.4804 )
n * 0.0294 = 0.3945
n = 13.43 Years
Part B:

Particulars Amount
Present Value $         810.00
Future Value $      1,821.00
Int Rate per period 8.0000%

Future Value = Cash Flow * ( 1 + r )^n
$ 1821 = $ 810 ( 1 + 0.08 ) ^ n
( 1 + 0.08 ) ^ n = $ 1821 / $ 810
1.08 ^ n = 2.2481
Take Log on Both sides
Log ( 1.08 ^ n ) = Log ( 2.2481 )
Log ( a^b ) = b * Log (a)
n * Log ( 1.08 ) = Log ( 2.2481 )
n * 0.0334 = 0.3518
n = 10.53 Years
Part C:

Particulars Amount
Present Value $    18,400.00
Future Value $ 289,715.00
Int Rate per period 9.0000%

Future Value = Cash Flow * ( 1 + r )^n
$ 289715 = $ 18400 ( 1 + 0.09 ) ^ n
( 1 + 0.09 ) ^ n = $ 289715 / $ 18400
1.09 ^ n = 15.7454
Take Log on Both sides
Log ( 1.09 ^ n ) = Log ( 15.7454 )
Log ( a^b ) = b * Log (a)
n * Log ( 1.09 ) = Log ( 15.7454 )
n * 0.0374 = 1.1972
n = 31.99 Years
Part D:

Particulars Amount
Present Value $    21,500.00
Future Value $ 430,258.00
Int Rate per period 11.0000%

Future Value = Cash Flow * ( 1 + r )^n
$ 430258 = $ 21500 ( 1 + 0.11 ) ^ n
( 1 + 0.11 ) ^ n = $ 430258 / $ 21500
1.11 ^ n = 20.012
Take Log on Both sides
Log ( 1.11 ^ n ) = Log ( 20.012 )
Log ( a^b ) = b * Log (a)
n * Log ( 1.11 ) = Log ( 20.012 )
n * 0.0453 = 1.3013
n = 28.71 Years


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