Question

In: Economics

company is producing 2 items A and B joint]y in fixed proportions of 1 :1 ....

company is producing 2 items A and B joint]y in fixed proportions of 1 :1 .

The following indicate their market demand functions: QA : 700 - 1 00 PA and QB : 500 - 200 P B. The MC of the joint operations is constant at Rs- 2 per unit

What quantities of A and B will company produce for optimum profits? (b) Will the company need to store in inventory at least one of the items or both items?
Support your answer with calculations.

Solutions

Expert Solution

To find the profit maximizing quantity and price for good A and B we need to use the profit maximizing condition, marginal revenue = marginal cost.

So let's calculate the profit maximizing quantity and price for good A.

First we need to inverse demand function for good A,

QA = 700 - 100PA

100PA = 700 - QA

PA = 7 - QA/100

Total revenue = PA × QA

Total revenue = (7 - QA/100) × QA

Differentiating both the sides with respect to QA to calculate marginal revenue,

Marginal revenue = (7 - QA/100)×1 + QA(-1/100)

Marginal revenue = 7 - 2QA/100

And marginal cost of production = 2

At profit maximizing quantity, MR=MC

7 - 2QA/100 = 2

700 - 2QA = 200

2QA = 700 - 200

QA = 500/2

QA* = 250

Putting QA in demand function we get,

PA = 7- QA/100

PA = 7- 250/100

PA = 7 - 2.5

PA* = 4.5

So the profit maximizing price PA* and quantity QA* for good A is 4.5 and 250 respectively.

Now let's calculate the profit maximizing price and quantity for good B,

QB = 500 - 200PB

200PB = 500 - QB

PB = (500 - QB)/200

PB = 5/2 - QB/200

Total revenue = PB×QB

Total revenue = (5/2 - QB/200)×QB

Differentiating both the sides with respect to QB to calculate the marginal revenue,

Marginal revenue = (5/2 - QB/200) × 1 + QB(-1/200)

Marginal revenue = 5/2 - 2QB/200

Marginal revenue = (500 - 2QB)/200

And putting MR=MC,

(500 - 2QB)/200 = 2

500 - 2QB = 400

2QB = 500 - 400

QB* = 100/2 = 50

Putting QB in the demand function we get,

PB = 5/2 - QB/200

PB = 5/2 - 50/200

PB = 5/2 - 1/4

PB* = (10 - 1)/4

PB* = 9/4 = 2.25

So the profit maximizing price PB* and quantity QB* for good B is 2.25 and 50 respectively.

But note that the company produces good A and B jointly in 1:1, that is to say they are producing good A and good B in equal numbers.

So the company needs to produce 250 units of good A to maximize profit from Good A but for producing 250 units of good A they'll have to produce 250 units of good B also. But as we have already calculated that the profit maximizing quantity of good B is only 50. So out of 250 units of good B company is going to sell only 50 units of good B, and rest will stored as inventory. So the amount of inventory for good B will be,

Inventory = total production - total sell

Inventory = 250 - 50

Inventory = 200.

So the company will need to store inventory of good B which is equal to 200 units.


Related Solutions

A company produces chairs and wood chips in fixed proportions in the same or joint production...
A company produces chairs and wood chips in fixed proportions in the same or joint production process : every chair produces one kg of wooden chips  Q function for chairs: Q c = 1800 – 20 Pc  Q function for wooden chips: Q w = 900- 1000 Pw  MC is Rs. 25 per unit of production – that is one chair + 1 kg chips  Will it be profitable to sell all the wood chips? (i)...
34. Consider a firm producing and selling joint products produced in variable proportions in two competitive...
34. Consider a firm producing and selling joint products produced in variable proportions in two competitive markets. For a given level of TC (or a level TR), the profit-maximizing combination of QA and QB requires _______, where PA = price of A, PB = price of B, CA = cost of A and CB = cost of B. MC of A and B can be used for CA and CB. A. P_A/C_A =P_B/C_B B. P_A/C_B =P_B/C_A C. P_A/C_A -P_B/C_B =1....
Let the joint p.d.f f(x,y) = 1 for 0 <= x <= 2, 0 <= y...
Let the joint p.d.f f(x,y) = 1 for 0 <= x <= 2, 0 <= y <= 1, 2*y <= x. (And 0 otherwise) Let the random variable W = X + Y. Without knowing the p.d.f of W, what interval of w values holds at least 60% of the probability?
Let X and Y have the joint pdf f(x,y)=(3/2)x^2 (1-|y|) , -1<x<1, -1<y<1. Calculate Var(X). Calculate...
Let X and Y have the joint pdf f(x,y)=(3/2)x^2 (1-|y|) , -1<x<1, -1<y<1. Calculate Var(X). Calculate Var(Y). P(−X≤Y).
Let X and Y have the joint probabilitydensity function (pdf):?(?, ?) = 3/2 ?2(1...
Let X and Y have the joint probability density function (pdf):   f(x, y) = 3/2 x2(1 − y),        − 1 < x < 1,      − 1 < y < 1 Find P(0 < Y < X). Find the respective marginal pdfs of X and Y. Are X and Y independent? Find the conditional pdf of X give Y = y, and E(X|Y = 0.5).  
If the joint probability distribution of X and Y f(x, y) = (x + y)/2
If the joint probability distribution of X and Y f(x, y) = (x + y)/2, x=0,1,2,3; y=0,1,2, Compute the following a. P(X≤2,Y =1) b. P(X>2,Y ≤1) c. P(X>Y) d. P(X+Y=4)
Let X and Y have joint pdf f(x,y)=k(x+y), for 0<=x<=1 and 0<=y<=1. a) Find k. b)...
Let X and Y have joint pdf f(x,y)=k(x+y), for 0<=x<=1 and 0<=y<=1. a) Find k. b) Find the joint cumulative density function of (X,Y) c) Find the marginal pdf of X and Y. d) Find Pr[Y<X2] and Pr[X+Y>0.5]
2. The joint pmf of ? and ? is given by ??,? (?, ?) = (x+y)/27  ???...
2. The joint pmf of ? and ? is given by ??,? (?, ?) = (x+y)/27  ??? ? = 0, 1,2; ? = 1, 2, 3, and ??,? (?, ?) = 0 otherwise. a. Find ?(?|? = ?) for all ? = 0,1, 2. b. Find ?(3 + 0.2?|? = 2).
Bob always consumes creamer (x) and coffee (y) in fixed proportions. He uses two creamers for...
Bob always consumes creamer (x) and coffee (y) in fixed proportions. He uses two creamers for every coffee such that his utility function is given by U(x,y)=min{x,2y}. Given that creamer costs $1 and a coffee costs $3, find Bob's optimal consumption of creamer and coffee if he has $25 to spend.
4. The joint density function of (X, Y ) is f(x,y)=2(x+y), 0≤y≤x≤1 . Find the correlation...
4. The joint density function of (X, Y ) is f(x,y)=2(x+y), 0≤y≤x≤1 . Find the correlation coefficient ρX,Y . 5. The height of female students in KU follows a normal distribution with mean 165.3 cm and s.d. 7.3cm. The height of male students in KU follows a normal distribution with mean 175.2 cm and s.d. 9.2cm. What is the probability that a random female student is taller than a male student in KU?
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT