Question

In: Statistics and Probability

1970’s 1980’s 1990’s 97 105 78 105 108 87 109 106 90 87 114 87 96...

1970’s

1980’s

1990’s

97

105

78

105

108

87

109

106

90

87

114

87

96

111

113

102

111

90

102

115

99

114

114

97

118

102

108

113

123

92

This table uses the data file that contains the scores of the winning teams from the final NBA Championship game. I would like to know if the average winning score is the same for each decade listed in the table. Test the claim that the samples all come from populations with the same mean. Use a significance level of 0.05.

  

  • Mean of 1970’s data:

  • Mean of 1980’s data:

  • Mean of 1990’s data:

  • Write each statement:

  • (null hypothesis):
  • (alternative hypothesis):
  • Write the “test statistic” here:
  • Write the P-value here:

REJECT    YES or NO

  • What is your conclusion? Do all of the samples come from populations with the same mean or is at least one group different?

Solutions

Expert Solution

  • Mean of 1970’s data:
  • Mean of 1980’s data:
  • Mean of 1990’s data:

In this example, the hypotheses are:

Null hypothesis There is no significant difference in the average winning score in each decade.
Alternative hypothesis At least one the average winning score is different among the three decade.

Null hypothesis H0: μ1 = μ2 = μ3 = μ4

Alternative hypothesis H1: The means are not all equal.

Significance level α = 0.05

Equal variances were assumed for the analysis.

Factor Information

Factor Levels Values
Decade 3 1970’s, 1980’s, 1990’s

The test statistic for testing H0: μ1 = μ2 = ... = μ4 is:

The test statistic for testing H0: μ1 = μ2 = ... = μ4 is:

where

  • = individual observation,
  • = sample mean of the jth treatment (or group),
  • = overall sample mean,
  • k = the number of treatments or independent comparison groups, and
  • N = total number of observations or total sample size.

In order to determine the critical value of F we need degrees of freedom, df1=k-1 and df2=N-k. In this example, df1=k-1=3-1=2 and df2=N-k=30-3=27.

The critical value is

and the decision rule is as follows: Reject H0 if F > 3.3541.

Analysis of Variance

Source DF Adj SS Adj MS F-Value P-Value
Factor 2 1433 716.4 9.12 0.0009
Error 27 2122 78.59
Total 29 3555

P-value=0.0009

Conclusion:

We reject H0 because F-value=9.12 > F-critical value= 3.3541 and also P-value=0.0009< level of significance=0.05.

We have statistically significant evidence at α=0.05

Hence, At least one the average winning score is different among the three decade.


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