In: Statistics and Probability
Suppose that a recent article stated that the mean time spent in jail by a first-time convicted
burglar is 2.2 years. A study was then done to see if the mean time has increased in the new
century. A random sample of 26 first-time convicted burglars in a recent year was picked. The
mean length of time in jail from the survey was three years with a standard deviation of 1.8
years. Conduct a hypothesis test to determine if the mean length of jail time has increased.
Assume the distribution of the jail times is approximately normal and use α=0.01.
Solution:
Given:
the mean time spent in jail by a first-time convicted burglar is 2.2 years.
Thus Mean =
Sample size = n = 26
Sample mean =
Sample standard deviation =s = 1.8
We have to test if the mean length of jail time has increased
Level of significance = 0.01
Step 1) State H0 and H1:
Vs
Step 2) Test statistic:
Step 3) t critical value
df = n - 1 = 26 -1 = 25
Level of significance = 0.01
Since this right tailed( one tailed) test , look for one tail area = 0.01 and df = 25
t critical value = 2.485
Step 4) Decision Rule:
Reject null hypothesis H0, if absolute t test statistic value > t critical value = 2.485 , otherwise we fail to reject H0
Since t test statistic value = 2.266< t critical value = 2.485 , we fail to reject H0.
Step 5) Conclusion:
At 0.01 level of significance, there is not sufficient evidence to conclude that: the mean length of jail time has increased.