Question

In: Biology

Male redback spiders present themselves for consumption to female redback spiders after they have mated with...

Male redback spiders present themselves for consumption to female redback spiders after they have mated with the female spiders. Female spiders eat the male spiders resulting in sexual cannibalism. What is the best way to characterize the evolutionary changes in redback spider behavior that occur over time due to natural selection?

Group of answer choices:

a) The proportion of redback spiders that performed sexual cannibalism increased in a population over time.

b) Environments where food is scarce cause specific mutations for sexual cannibalism to occur in individual redback spiders.

c) A mutation resulting in sexual cannibalism occurred to meet the changing needs of the redback spider.

d) Individuals in the redback spider population increasingly perform sexual cannibalism over their lifetime.

Solutions

Expert Solution

Evolution by natural selection occurs when organisms with favorable traits reproduce more, thus increasing the frequency of that trait in a population gradually over time.All known red spiders perform sexual cannibalism because the proportion of redback spiders that performed sexual cannibalism increased in a population over time owing to certain fitness value provided by that behavioral trait.Therefore option a) is the right answer.

Option b) and c) are wrong because natural selection directly acts on phenotype and not on genotype.Also it is not likely that a single mutation can result in a complex behavioral trait like cannibalism in an individual.

Option d) is wrong because it does not clearly mention the increase in frequency of spiders performing sexual cannibalism in a population over a long period of time.One generation of spiders performing cannibalism in their lifetime is not enough to cause evolution by natural selection.


Related Solutions

In the fruit fly, Drosophila melanogaster, a wingless female fly is mated to a male that...
In the fruit fly, Drosophila melanogaster, a wingless female fly is mated to a male that is white-bodied and legless. Assume that all alleles causing these phenotypes are recessive. Phenotypically wild-type F1 female progeny were mated to fully homozygous (mutant) males, and the following progeny were observed: Phenotypes Number Observed wingless                           324 wild-type                             34 white, wingless                 135 white                                   8 white, legless                   319 hairless, white, legless     32 hairless                              140 hairless, legless               9 (a) With respect to the three genes mentioned in the problem, what are the genotypes...
A female fruit fly with singed bristles was mated with a male from a true-breeding wild-type...
A female fruit fly with singed bristles was mated with a male from a true-breeding wild-type stock with long bristles. All of the F1 females had wild-type long bristles and all of the F1 males had singed bristles. If the F1 flies are intercrossed, the expected ratio of long to singed bristles in the F2 flies is Multiple Choice 3:1 in both sexes. 3:1 in females, while all the males will have singed bristles. 1:1 in both sexes. 1:1 in...
1. In Drosophila again, a red-eyed heterozygous female is mated with a red-eyed male. A) What...
1. In Drosophila again, a red-eyed heterozygous female is mated with a red-eyed male. A) What are the phenotypes of their male offspring? B) What is the expected ratio of those phenotypes (in their sons)? 2. A man and woman plan to have children. The woman is a hemophiliac (she suffers from hemophilia, which is an X-linked disorder), but the man is not a hemophiliac. A) What are the chances that their sons will be hemophiliacs? B) What are the...
In health insurance markets, individuals have an incentive to present themselves as healthier as they are,...
In health insurance markets, individuals have an incentive to present themselves as healthier as they are, which can lead to a type of market failure called moral hazard. Question 23 options: True False
Male and female grades in one of the subjects taught to male and female students came...
Male and female grades in one of the subjects taught to male and female students came as follows: Excellent Very Good Good Acceptable Failed Female 3 11 12 4 1 Male 2 7 7 7 3 Use SPSS and study the relationship between student type and grade, and answer the following questions: A- Formulate the appropriate null hypothesis. B- Determine the value of the appropriate level of significance. C- Determine the value of the Chi square. W- Set the degrees...
Probability Theory. In a given population of two-earner male-female couples, male earnings have a mean of...
Probability Theory. In a given population of two-earner male-female couples, male earnings have a mean of $50,000 per year and a standard deviation of $15,000. Female earnings have a mean of $48,000 per year and a standard deviation of $13,000. The correlation between male and female earnings for a couple is 0.90. Let C denote the combined earnings for a randomly selected couple. c. What is the standard deviation of C?
A virgin Drosophila female whose thorax bristles are very short is mated with a males having...
A virgin Drosophila female whose thorax bristles are very short is mated with a males having normal (long) bristles. The F1 progeny are 1/3 short-bristle females, 1/3 long bristle females, and 1/3 long bristle males. A cross of the F1 long bristle females with their brothers gives only long bristle F2 progeny. A cross of short bristle females with their brothers gave 1/3 long bristle females, 1/3 short bristle females, and 1/3 long bristle males. A) Explain what is going...
In the fruit fly, Drosophila melanogaster, a spineless (sp, no wing bristles) female fly is mated...
In the fruit fly, Drosophila melanogaster, a spineless (sp, no wing bristles) female fly is mated to a male that is claret (cl, dark eyes) and hairless (h, no thoracic bristles). Phenotypically wild type F1 female progeny were mated to fully homozygous (mutant) males and the following progeny (1000 total) were observed.             PHENOTYPES                    NUMBER OBSERVED             spineless                                             316             wild                                                         8             claret, spineless                                  136             claret                                                     37             claret, hairless                                    304             hairless, claret, spineless                     12             hairless                                               144             hairless, spineless                                43 What is the correct gene map for these genes?...
The heights, in inches, for 120 people (male and female) have been measured. The results are...
The heights, in inches, for 120 people (male and female) have been measured. The results are presented: Download the data Heights sample data: 65.14 66.74 65.37 65.08 69.62 69.34 70.32 62.38 67.77 64.1 65.43 63.21 66.74 62.22 68.76 67.67 68.29 66.62 66.74 66.8 63.06 70.33 67.36 64.78 67.2 68 66.09 67.81 67.58 69.13 65.06 62.91 64.05 66.49 60.33 68.98 65.57 63.88 64.62 66.27 68.32 61.34 63.95 71.76 63.1 70.3 64.89 66.74 67.77 64.22 69.18 71.19 67.43 63.7 69.87 70.1 65.07...
White eye is a recessive X-linked mutant in fruit flies. A wild type male is mated...
White eye is a recessive X-linked mutant in fruit flies. A wild type male is mated to a white-eyed female. What is the probability that an F1 son will be white eyed? A. 0 B. 0.25 C. 0.5 D. 0.75 E. 1.0
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT