Question

Male and female grades in one of the subjects taught to male and female students came as follows:

	Excellent	Very Good	Good	Acceptable	Failed
Female	3	11	12	4	1
Male	2	7	7	7	3

Use SPSS and study the relationship between student type and grade, and answer the following questions:

A- Formulate the appropriate null hypothesis.

B- Determine the value of the appropriate level of significance.

C- Determine the value of the Chi square.

W- Set the degrees of freedom.

C- Extract the value of P ~ value.

H- Test your zero hypothesis, and make an appropriate decision about it, and what does it mean?

Answer 1

Result:

Use SPSS and study the relationship between student type and grade, and answer the following questions:

A- Formulate the appropriate null hypothesis.

Ho: There is no association between student type and grade

H1: There is an association between student type and grade

B- Determine the value of the appropriate level of significance.

Level of significance: 0.05

C- Determine the value of the Chi square.

Chi square =3.814

W- Set the degrees of freedom.

Degrees of freedom : 4

C- Extract the value of P ~ value.

P value = 0.432

H- Test your zero hypothesis, and make an appropriate decision about it, and what does it mean?

Since p value 0.432 > level of significance 0.05, Ho is not rejected.

We conclude that there is no association between student type and grade.

Enter data as below in SPSS and label the data.

SPSS command used for analysis:

WEIGHT BY wt.

CROSSTABS

/TABLES=row BY col

/FORMAT=AVALUE TABLES

/STATISTICS=CHISQ

/CELLS=COUNT

/COUNT ROUND CELL.

SPSS output:

row * col Crosstabulation
Count
	col	Total
Excellent	Very Good	Good	Acceptable	Failed
row	Female	3	11	12	4	1	31
Male	2	7	7	7	3	26
Total	5	18	19	11	4	57

Chi-Square Tests
	Value	df	Asymptotic Significance (2-sided)
Pearson Chi-Square	3.814a	4	0.432
Likelihood Ratio	3.865	4	0.425
Linear-by-Linear Association	2.322	1	0.128
N of Valid Cases	57
a. 4 cells (40.0%) have expected count less than 5. The minimum expected count is 1.82.