Question

In: Statistics and Probability

My second question A mental health service agency is conducting a study of how clients pay...

My second question

A mental health service agency is conducting a study of how clients pay for the counseling services they receive. The agency accepts payment in one of four ways: in person, by mail, by credit card, or by third-party insurance. The agency randomly sampled 400 clients to determine if there is a relationship between the client’s age and the payment method used. The following sample results were obtained:

Counseling Service Payments

Payment Method Age of Client
20-30 31-40 41-50 Over 50
In Person 8 12 11 13
By Mail 29 67 72 50
By Credit Card 26 19 5 7
By Third-Party Insurance 23 35 17 6

Based on the sample data, can the agency conclude there is a relationship between the age of the client and the payment method used? Conduct the appropriate test at the α = 0.01 level of significance.

Solutions

Expert Solution

Given table data is as below
MATRIX col1 col2 col3 TOTALS TOTALS
row 2 8 12 11 13 44
row 3 29 67 72 50 218
row 3 26 19 5 7 57
row 4 23 35 17 6 81
TOTALS 86 133 105 76 400
------------------------------------------------------------------

calculation formula for E table matrix
E-TABLE col1 col2 col3 col4
row 2 row1*col1/N row1*col2/N row1*col3/N row1*col4/N
row 3 row2*col1/N row2*col2/N row2*col3/N row2*col4/N
row 3 row3*col1/N row3*col2/N row3*col3/N row3*col4/N
row 4 row4*col1/N row4*col2/N row4*col3/N row4*col4/N
------------------------------------------------------------------

expected frequencies calculated by applying E - table matrix formulae
E-TABLE col1 col2 col3 col4
row 2 9.46 14.63 11.55 8.36
row 3 46.87 72.485 57.225 41.42
row 3 12.255 18.953 14.963 10.83
row 4 17.415 26.933 21.263 15.39
------------------------------------------------------------------

calculate chisquare test statistic using given observed frequencies, calculated expected frequencies from above
Oi Ei Oi-Ei (Oi-Ei)^2 (Oi-Ei)^2/Ei
8 9.46 -1.46 2.132 0.225
12 14.63 -2.63 6.917 0.473
11 11.55 -0.55 0.303 0.026
13 8.36 4.64 21.53 2.575
29 46.87 -17.87 319.337 6.813
67 72.485 -5.485 30.085 0.415
72 57.225 14.775 218.301 3.815
50 41.42 8.58 73.616 1.777
26 12.255 13.745 188.925 15.416
19 18.953 0.047 0.002 0
5 14.963 -9.963 99.261 6.634
7 10.83 -3.83 14.669 1.354
23 17.415 5.585 31.192 1.791
35 26.933 8.067 65.076 2.416
17 21.263 -4.263 18.173 0.855
6 15.39 -9.39 88.172 5.729
ᴪ^2 o = 50.314
------------------------------------------------------------------

set up null vs alternative as
null, Ho: no relation b/w X and Y OR X and Y are independent
alternative, H1: exists a relation b/w X and Y OR X and Y are dependent
level of significance, α = 0.01
from standard normal table, chi square value at right tailed, ᴪ^2 α/2 =21.666
since our test is right tailed,reject Ho when ᴪ^2 o > 21.666
we use test statistic ᴪ^2 o = Σ(Oi-Ei)^2/Ei
from the table , ᴪ^2 o = 50.314
critical value
the value of |ᴪ^2 α| at los 0.01 with d.f (r-1)(c-1)= ( 4 -1 ) * ( 4 - 1 ) = 3 * 3 = 9 is 21.666
we got | ᴪ^2| =50.314 & | ᴪ^2 α | =21.666
make decision
hence value of | ᴪ^2 o | > | ᴪ^2 α| and here we reject Ho
ᴪ^2 p_value =0


ANSWERS
---------------
null, Ho: no relation b/w X and Y OR X and Y are independent
alternative, H1: exists a relation b/w X and Y OR X and Y are dependent
test statistic: 50.314
critical value: 21.666
p-value:0
decision: reject Ho

we have enough evidence to support the claim that  the agency conclude there is a relationship between the age of the client and the payment method used.


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