Question

An object of mass 0.50 kg is released from the top of a building of height 2 m. The object experiences a horizontal constant force of 1.1 N due to a wind blowing parallel to the face of the building.

(a) Find the time it takes for the object to strike the ground. _____s

(b) What is the magnitude of the acceleration of the object? ______m/s2

(c) Through what horizontal distance does the object move before it hits the ground? _____m

Answer 1

   Given Data

                    m =0.5 kg

                    h=2m

                   F=1.1N

(a)Formula = root(2y/g)   where y=2m

                   = root(4/9.81)

                  = root(0.4077)

                   =0.6385 sec

(b) Formula A=root(Ax^2+Ay^2)

                    Ax=1.1/0.50

                         =2.2 m/s^2

                   Ay=9.8 m/s^2

                    A=root(Ax^2+Ay^2)

                       = root(4.84+96.23)

                        =root(102.07)

                       =10.53 m/s^2

(c) Formula X=(1/2)*Ax*t^2

                      =0.5*2.2*0.47039

                     =0.4484 meters