In: Statistics and Probability
Problem 1. The director of manufacturing at a clothing factory needs to determine whether a new machine is producing a particular type of cloth according to the manufacturer’s specifications, which indicate that the cloth should have a mean breaking strength of 70 pounds and a standard deviation of 3.5 ponds. A sample of 49 pieces of cloth reveals a sample mean breaking strength of 69.1 pounds. Is there evidence that the machine is not meeting the manufacturer’s specifications for mean breaking strength?
Solution :
Given that
= 70
= 69.1
=3.5
n = 49
This is the two tailed test .
The null and alternative hypothesis is ,
H0 : = 70
Ha : 70
Test statistic = z
= ( - ) / / n
= ( 69.1 - 70 ) / 3.5 / 49
= -1.8
The test statistic = -1.8
P-value = 2 * P ( Z < -1.8 )
= 2 * 0.0359
= 0.0718
P - value = 0.0718
= 0.05
0.0718 > 0.0718
P-value >
Fail to reject the null hypothesis .
There is insufficient evidence to claim