Question

The data show systolic and diastolic blood pressure of certain people. Find the regression​ equation, letting the systolic reading be the independent​ (x) variable. Find the best predicted diastolic pressure for a person with a systolic reading of

127127.

Is the predicted value close to

96.696.6​,

which was the actual diastolic​ reading? Use a significance level of 0.05.

Systolic	135135	125125	114114	143143	130130	135135	126126	117117
Diastolic	9898	6868	8282	102102	7070	101101	9494	5858

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Click the icon to view the critical values of the Pearson correlation coefficient r.

What is the regression​ equation?

ModifyingAbove y with caretyequals=negative 72.09−72.09plus+1.221.22x

​ (Round to two decimal places as​ needed.)What is the best predicted diastolic pressure for a person with a systolic reading of

127127​?

The best predicted diastolic pressure for a person with a systolic reading of

127127

is

nothing.

Answer 1

Solution :

Given that systolic x as 135,125,114,143,130,135,126,117

diastolic y as 98,68,82,102,70,101,94,58

=> The regression equation is y = -72.09 + 1.22*x (rounded)

==> The best predicted diastolic pressure for a person with a systolic reading of 127 is

=> y = -72.09 + 1.22*127 = 82.85