Add or subtract the following 2’s complement form signed
numbers, then convert the entire problem to decimal and
confirm:
110110 + 111000
001100 – 011100
BUFFER PROBLEMS
3. Start with either the conjugate acid or base and add a strong
base or strong acid (conjugate acid plus strong base forms the
conjugate base and water; conjugate base plus strong acid forms the
conjugate acid): What is the pH of 0.5 L of a 0.1 M acetic acid
solution to which 0.73 g of NaOH are added? The pKa of acetic acid
is 4.76.
Convert each of the following 5-digit 6’s complement base 7
numbers to 9-digit 4’s complement base 4. Be careful, show all your
reasoning/arithmetic, and make no unwarranted assumptions!
(a) 50135
(b) 11402
Add in the indicated base
56 base 8 + 75 base 8 =
Subtract in the indicated base
230 base 5 + 32 base 5
Multiply in the indicated base:
42 base 5 x 43 base 5
65 base 7 x 43 base 7
Formula 3 = y( x) = (x^3 - 2x^2 + 5x – 25)/40
In terms of hand calculations, determine the root of Formula 3
given above by using the Newton-Raphson method. Start with an
initial guess of xo = -4, i.e., yo = y(-4). Label your successive
solution pairs as(xo yo), (x1, y1), (x2, y2)….Work out your
solution (at each step) to an accuracy of two places below the
decimal point. Your overall solution is to display full detail of
every...
i need to convert decimal to twos complement binary and then add
the binary digits but I am unable to do it. I am only allowed to
use string, can anyone help me out please. i need the code
urgently.
#include
#include
#include
#include
using namespace std;
string reverse(string s)
{
string x = "";
for (long i = s.length() - 1; i >= 0; i--)
{
x += s[i];
}
return x;
}
string twosComplementStringsAddition(string A, string B)
{...
Digital arithmetic:
a) Convert +35 to 2-complement
b) Convert -35 to 2-complement
c) Convert 2-complement from 1101 1101 to decimal
d) Add 35 - 35 in binary
That is, PDEs of the general form A(x, y, u) ∂u(x, y) ∂x + B(x,
y, u) ∂u(x, y) ∂y = C(x, y, u), (1) for some A, B and C. To solve
such PDEs we first find characteristics, curves in the solution
space (x, y, u) parametrically given by (x(τ ), y(τ ), u(τ )),
which satisfy dx dτ = A(x, y, u), dy dτ = b(x, y, u), du dτ = C(x,
y, u). (2) We find solutions...