In: Statistics and Probability
The following data is representative of that reported in an article on nitrogen emissions, with x = burner area liberation rate (MBtu/hr-ft2) and y = NOx emission rate (ppm):
x | 100 | 125 | 125 | 150 | 150 | 200 | 200 | 250 | 250 | 300 | 300 | 350 | 400 | 400 |
y | 160 | 140 | 190 | 210 | 180 | 320 | 270 | 410 | 430 | 450 | 390 | 610 | 610 | 670 |
(a) Assuming that the simple linear regression model is valid,
obtain the least squares estimate of the true regression line.
(Round all numerical values to four decimal places.)
y =
(b) What is the estimate of expected NOx
emission rate when burner area liberation rate equals 215? (Round
your answer to two decimal places.)
ppm
(c) Estimate the amount by which you expect NOx
emission rate to change when burner area liberation rate is
decreased by 40. (Round your answer to two decimal places.)
ppm
Folloiwng table shows the caculations:
X | Y | X^2 | Y^2 | XY | |
100 | 160 | 10000 | 25600 | 16000 | |
125 | 140 | 15625 | 19600 | 17500 | |
125 | 190 | 15625 | 36100 | 23750 | |
150 | 210 | 22500 | 44100 | 31500 | |
150 | 180 | 22500 | 32400 | 27000 | |
200 | 320 | 40000 | 102400 | 64000 | |
200 | 270 | 40000 | 72900 | 54000 | |
250 | 410 | 62500 | 168100 | 102500 | |
250 | 430 | 62500 | 184900 | 107500 | |
300 | 450 | 90000 | 202500 | 135000 | |
300 | 390 | 90000 | 152100 | 117000 | |
350 | 610 | 122500 | 372100 | 213500 | |
400 | 610 | 160000 | 372100 | 244000 | |
400 | 670 | 160000 | 448900 | 268000 | |
Total | 3300 | 5040 | 913750 | 2233800 | 1421250 |
(b)
Answer: 324.44 ppm
(c)
For each unit decrease in burner area liberation rate, NOx is decreased by 1.7164 units. So the amount by which you expect NOx emission rate to change (that is decreased by) when burner area liberation rate is decreased by 40 is
40 * 1.7164 = 68.656
Answer: 68.66 ppm