Question

According to a regional Bar​ Association, approximately 60​% of the people who take the bar exam to practice law in the region pass the exam. Find the approximate probability that at least 61​% of 500 randomly sampled people taking the bar exam will pass. Answer the questions below.

The sample proportion is 0.610 What is the population​ proportion?

Answer 1

Solution

Given that,

population proportion = p = 0.60

1 - p = 1 - 0.60 = 0.40

n = 500

= p = 0.60

=  [p( 1 - p ) / n] = [(0.60 * 0.40 ) / 500 ] = 0.0219

P( 0.610 ) = 1 - P( 0.610 )

= 1 - P(( - ) / ( 0.610 - 0.60 ) / 0.0219 )

= 1 - P(z 0.46 )

Using z table

= 1 - 0.6772

= 0.3228