In: Statistics and Probability
According to a regional Bar Association, approximately 60% of the people who take the bar exam to practice law in the region pass the exam. Find the approximate probability that at least 61% of 500 randomly sampled people taking the bar exam will pass. Answer the questions below.
The sample proportion is 0.610 What is the population proportion?
Solution
Given that,
population proportion = p = 0.60
1 - p = 1 - 0.60 = 0.40
n = 500
= p = 0.60
= [p( 1 - p ) / n] = [(0.60 * 0.40 ) / 500 ] = 0.0219
P( 0.610 ) = 1 - P( 0.610 )
= 1 - P(( - ) / ( 0.610 - 0.60 ) / 0.0219 )
= 1 - P(z 0.46 )
Using z table
= 1 - 0.6772
= 0.3228