In: Statistics and Probability
The accompanying data table describes results from groups of 10 births from 10 different sets of parents. The random variable x represents the number of girls among 10 children.
x P(x)
0 0.001
1 0.018
2 0.036
3 0.116
4 0.196
5 0.246
6 0.195
7 0.114
8 0.038
9 0.017
10 0.023
Find the maximum and minimum usual value.
Solution :
x | P(x) | x * P(x) | x2 * P(x) |
0 | 0.001 | 0 | 0 |
1 | 0.018 | 0.018 | 0.018 |
2 | 0.036 | 0.072 | 0.144 |
3 | 0.116 | 0.348 | 1.044 |
4 | 0.196 | 0.784 | 3.136 |
5 | 0.246 | 1.23 | 6.15 |
6 | 0.195 | 1.17 | 7.02 |
7 | 0.114 | 0.798 | 5.586 |
8 | 0.038 | 0.304 | 2.432 |
9 | 0.017 | 0.153 | 1.377 |
10 | 0.023 | 0.23 | 2.3 |
Sum | 1 | 5.107 | 29.207 |
Mean = = X * P(X) = 5.107
Standard deviation =
=X 2 * P(X) - 2
= (29.207 - 5.1072)
= 1.768
maximum usual value
= mean + 2 * Standard deviation
= 5.107 + 2 * 1.768
= 8.643
minimum usual value
= mean - 2 * Standard deviation
= 5.107 - 2 * 1.768
= 1.571