In: Statistics and Probability
The accompanying data table describes results from groups of 10 births from 10 different sets of parents. The random variable x represents the number of girls among 10 children.
x   P(x)
0   0.001
1   0.018
2   0.036
3   0.116
4   0.196
5   0.246
6   0.195
7   0.114
8   0.038
9   0.017
10   0.023
Find the maximum and minimum usual value.
Solution :
| x | P(x) | x * P(x) | x2 * P(x) | 
| 0 | 0.001 | 0 | 0 | 
| 1 | 0.018 | 0.018 | 0.018 | 
| 2 | 0.036 | 0.072 | 0.144 | 
| 3 | 0.116 | 0.348 | 1.044 | 
| 4 | 0.196 | 0.784 | 3.136 | 
| 5 | 0.246 | 1.23 | 6.15 | 
| 6 | 0.195 | 1.17 | 7.02 | 
| 7 | 0.114 | 0.798 | 5.586 | 
| 8 | 0.038 | 0.304 | 2.432 | 
| 9 | 0.017 | 0.153 | 1.377 | 
| 10 | 0.023 | 0.23 | 2.3 | 
| Sum | 1 | 5.107 | 29.207 | 
Mean = 
 = 
X * P(X) = 5.107
Standard deviation = 
=
X
2 * P(X) - 
2
=  
(29.207
- 5.1072)
= 1.768
maximum usual value
= mean + 2 * Standard deviation
= 5.107 + 2 * 1.768
= 8.643
minimum usual value
= mean - 2 * Standard deviation
= 5.107 - 2 * 1.768
= 1.571