In: Chemistry
How will the following situations affect your final calculation of molarity of HC2H3O2? (higher, lower, unaffected. be specific) A) You wash the sides of the flask with deionized water to remove any vinegar of NaOH solution adhering to the side of the flask. B) You add 20 mL of water to the vinegar in the flask (assume no drops of vinegar adhere to the side of the flask). C) The tip of the buret is not filled when you start a titration but is filled when you finish the titration. D) The molarity of the standard NaOH solution is miscalulated and the true value is higher than the concentration given. E) As you are refilling your buret, some of the NaOH spills over the side and runs down the buret into the flask you intend to titrate.
A) You wash the sides of the flask with deionized water to remove any vinegar of NaOH solution adhering to the side of the flask.
Increase as you are bringing in more acetic acid Higher
B) You add 20 mL of water to the vinegar in the flask (assume no drops of vinegar adhere to the side of the flask).
Since you are adding water you are diluting the compound but if you use the whole material it will remain unchanged
C) The tip of the buret is not filled when you start a titration but is filled when you finish the titration.
Some volume that you estimated to be used was actually not used as it was used to fill the tip of the burette so acid estimated is more as base consumed is more higher.
D) The molarity of the standard NaOH solution is miscalulated and the true value is higher than the concentration given.
As the concentration is higher the actual acid consumed is lower so the acid will be estimated lower
E) As you are refilling your buret, some of the NaOH spills over the side and runs down the buret into the flask you intend to titrate.
As some acid is initially consumed the final estimation will be lower so the value will be lower