Question

If you have a boar’s ejaculate that has the following characteristics, please answer these questions. (show your calculations)

                            Characteristics

         Color           Creamy color

         Volume      200 mls

         Motility      60%

         % Alive       90

         % Normal   80

Number of live, normal and motile sperm needed for insemination = 2 X 10^9

Concentration of this ejaculate 250 million/ml

1. Total # of sows that can be bred with this ejaculate?
2. Total volume of extender needed to breed these sows? ______ml

How many ewes could be AI with the average rams ejaculate (data provided)? (show your calculations)

Concentration-    3.5 billion/ml

Volume               1.5 ml

Motility               90%

% Live                 85%

% Normal            95%

If a stallion’s ejaculate has 80% motility and a concentration of 500 million/ml, (a) how much of the neat cooled ejaculate would you need if the mare is to be bred with 4 billion live sperm?

1. _________ mls
2. How much extender would you add to this breeding dose (part A) to ship it to Maine for AI of a mare the next day? _______mls

Answer 1

Ans: As given in the question that the concentration of this ejaculate is 2.5*108 per ml and total volume is 200 mL so total number is 5*1010 in 200 mL and from these amount only 60% is motile,alive and normal which is 3*1010.

a) Number of sperms needed for insemination is 2*109 and we have 3*1010 sperms so total no. of sows that can be bred with this ejaculate is 15 as normal,motile and alive sperms for one insemination is 2*109 and we have 3*1010 sperms.

b) As discussed above that the semen concentration is 250*106 sperms/mL and from this only 60% is useful for insemination so useful concentration is 150*106 sperms/mL.

Extender or dilutent is a chemical medium used for. preservation, extension and protection of sperm cells. For breeding these sows the required sperm concentration is 150*106 sperms/mL and we have the concentration of 250*106 sperms/ml.

So if we assume we required 1 ml of exrtended semen than

mL of semen to be taken = 150/250= 0.6

ml of extender to add= 1-volume of semen= 0.4 mL

So for required concentration we have to add 0.4 mL of extender with 0.6 mL of semen. but the total volume of semen is 200 mL so the requires volume of extender to add is 200*0.4 which is 80 mL and amount of semen volume to be taken is 120 ml.

2) The concentration is 3.5*109 sperms/mL and total volume is 1.5 mL so total number of sperms is 5.25*109 sperms. Now from these 85% are live, normal and motile so their numbers is 4.5*109 sperms. Now about 100 million sperms or 108 sperms are required for 1 artificial insemination and total sperms we have is 4.5*109 so number of ewes artificially inseminated is 45.

3) a) As given in the question the concentration is 5*108 sperms/mL and from this only 80% is motile so useful sperms amount is equal to 4*108 sperms/mL. Now for breeding one mare the number of live sperms required is 4*109 and in 1 mL we have 4*108 sperms. So total volume needed for this insemination is 10 mL.

b) Now similarly the total concentration is 500*106 sperms/mL and required amount is 400*106 sperms/mL.

So if we assume we required 1 ml of exrtended semen than

mL of semen to be taken = 400/500= 0.8

ml of extender to add= 1-volume of semen= 0.2 mL.

So for required concentration we have to add 0.2 mL of extender with 0.8 mL of semen. but the total volume requires is 10 mL so the requires volume of extender to add is 10*0.2 which is 2 mL and amount of semen volume to be taken is 8 ml.