In: Statistics and Probability
The State Farm Insurance Company boasts that 90% of its customers who make claims are satisfied with the service. To check the accuracy of this declaration, the company conducts a survey wherein customers are asked whether they were satisfied with the quality of service. 153 were satisfied and 24 were not satisfied. Can we infer at the 5% level of significance that the satisfaction rate is less than 90%? (Use 4 decimal places in your initial work for this problem.)
1.a.Is the test statistic for this test Z or t?
1.b.What is the value of the test statistic of the test? ( Enter 0 if this value cannot be determined with the given information.)
1.c.What is the pvalue of the test? (Enter 0 if this value cannot be determined with the given information.)
1.d.What is the relevant bound of the rejection region? (Enter 0 if this value cannot be determined with the given information.)
1.e.
What decision should be made?
Select one:
a. Do not reject the null hypothesis
b. Can not be determined from given information
c. Reject the null hypothesis
d. Accept the null hypothesis
Result:
The State Farm Insurance Company boasts that 90% of its customers who make claims are satisfied with the service. To check the accuracy of this declaration, the company conducts a survey wherein customers are asked whether they were satisfied with the quality of service. 153 were satisfied and 24 were not satisfied. Can we infer at the 5% level of significance that the satisfaction rate is less than 90%? (Use 4 decimal places in your initial work for this problem.)
1.a.Is the test statistic for this test Z or t?
Z test
1.b.What is the value of the test statistic of the test? ( Enter 0 if this value cannot be determined with the given information.)
Ho: P=0.9, H1: P<0.9
Lower tail test

p=153/177=0.8644

z = -1.5785
1.c.What is the pvalue of the test? (Enter 0 if this value cannot be determined with the given information.)
P value = 0.0572
1.d.What is the relevant bound of the rejection region? (Enter 0 if this value cannot be determined with the given information.)
Table value of z at 0.05 level = -1.645
Rejection Region: Reject Ho if z < -1.645
1.e.
What decision should be made?
Calculated z = -1.5785 , not in the rejection region
The null hypothesis is not rejected.
Select one:
a. Do not reject the null hypothesis
| 
 Z Test of Hypothesis for the Proportion  | 
|
| 
 Data  | 
|
| 
 Null Hypothesis p =  | 
 0.9  | 
| 
 Level of Significance  | 
 0.05  | 
| 
 Number of Items of Interest  | 
 153  | 
| 
 Sample Size  | 
 177  | 
| 
 Intermediate Calculations  | 
|
| 
 Sample Proportion  | 
 0.8644  | 
| 
 Standard Error  | 
 0.0225  | 
| 
 Z Test Statistic  | 
 -1.5785  | 
| 
 Lower-Tail Test  | 
|
| 
 Lower Critical Value  | 
 -1.645  | 
| 
 p-Value  | 
 0.0572  | 
| 
 Do not reject the null hypothesis  | 
|