In: Statistics and Probability
The State Farm Insurance Company boasts that 90% of its customers who make claims are satisfied with the service. To check the accuracy of this declaration, the company conducts a survey wherein customers are asked whether they were satisfied with the quality of service. 153 were satisfied and 24 were not satisfied. Can we infer at the 5% level of significance that the satisfaction rate is less than 90%? (Use 4 decimal places in your initial work for this problem.)
1.a.Is the test statistic for this test Z or t?
1.b.What is the value of the test statistic of the test? ( Enter 0 if this value cannot be determined with the given information.)
1.c.What is the pvalue of the test? (Enter 0 if this value cannot be determined with the given information.)
1.d.What is the relevant bound of the rejection region? (Enter 0 if this value cannot be determined with the given information.)
1.e.
What decision should be made?
Select one:
a. Do not reject the null hypothesis
b. Can not be determined from given information
c. Reject the null hypothesis
d. Accept the null hypothesis
Result:
The State Farm Insurance Company boasts that 90% of its customers who make claims are satisfied with the service. To check the accuracy of this declaration, the company conducts a survey wherein customers are asked whether they were satisfied with the quality of service. 153 were satisfied and 24 were not satisfied. Can we infer at the 5% level of significance that the satisfaction rate is less than 90%? (Use 4 decimal places in your initial work for this problem.)
1.a.Is the test statistic for this test Z or t?
Z test
1.b.What is the value of the test statistic of the test? ( Enter 0 if this value cannot be determined with the given information.)
Ho: P=0.9, H1: P<0.9
Lower tail test
p=153/177=0.8644
z = -1.5785
1.c.What is the pvalue of the test? (Enter 0 if this value cannot be determined with the given information.)
P value = 0.0572
1.d.What is the relevant bound of the rejection region? (Enter 0 if this value cannot be determined with the given information.)
Table value of z at 0.05 level = -1.645
Rejection Region: Reject Ho if z < -1.645
1.e.
What decision should be made?
Calculated z = -1.5785 , not in the rejection region
The null hypothesis is not rejected.
Select one:
a. Do not reject the null hypothesis
Z Test of Hypothesis for the Proportion |
|
Data |
|
Null Hypothesis p = |
0.9 |
Level of Significance |
0.05 |
Number of Items of Interest |
153 |
Sample Size |
177 |
Intermediate Calculations |
|
Sample Proportion |
0.8644 |
Standard Error |
0.0225 |
Z Test Statistic |
-1.5785 |
Lower-Tail Test |
|
Lower Critical Value |
-1.645 |
p-Value |
0.0572 |
Do not reject the null hypothesis |