Question

In: Physics

A point charge +q is at the origin. A spherical Gaussian surface centered at the origin...

A point charge +q is at the origin. A spherical Gaussian surface centered at the origin encloses +q. So does a cubical surface centered at the origin and with edges parallel to the axes. Select "True" or "False" for each statement below.

1. Suppose (for this statement only), that q is moved from the origin but is still within both the surfaces. The flux through both surfaces is changed.

2.If the radius of the spherical Gaussian Surface is varied, the flux through it also varies.

3. The area vector and the E-Field vector point in the same direction for all points on the spherical surface.

4. The E-Field at all points on the spherical surface is equal due to spherical symmetry.

5. The Electric Flux through the spherical surface is less than that through the cubical surface.

Solutions

Expert Solution

1. Suppose (for this statement only), that q is moved from the origin but is still within both the surfaces. The flux through both surfaces is changed.--------False, as from Gauss law flux = Qin/eo, since here QIn not change, flux will not charge

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2.If the radius of the spherical Gaussian Surface is varied, the flux through it also varies.----True

as from GAuss law FLux = E.A = E* 4pi r^2 where r is radius

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3. The area vector and the E-Field vector point in the same direction for all points on the spherical surface.False as Electric field are always radial to the surface

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4. The E-Field at all points on the spherical surface is equal due to spherical symmetry.-------True

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5. The Electric Flux through the spherical surface is less than that through the cubical surface. False, since charges are same, flux will be same


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