In: Physics
A charge +Q is located at the origin and a second charge, +6 Q , is at distance d on the x-axis.
Part A Where should a third charge, q, be placed, so that all three charges will be in equilibrium? Express your answer numerically as a multiple of d
Part C What should be its magnitude, so that all three charges will be in equilibrium? Express your answer numerically as a multiple of Q
Since two charges +Q at the origin and a second charge +6Q at distance 'd' on the x- axis
Part A) . Third charge 'q' will be placed -
Since each charge has an electric field, and as both of them have a positive charge, the electric field from a charge is away from the charge 'q' , so the place of charge 'q' will be between the two charges +Q and +6 Q because the two charges will be in opposite direction and the net electric field will be zero (repulsive nature) at a certain distance between them.
Let us consider the distance between charge 'q' and +Q is 'm' show the distance between the charge 'q' and +6 Q will be 'd-m'.
Now , we have to find value of 'm' the place of the charge 'q' , where are the two electric fields at this point have same magnitude.
Let consider E1( electric field for +Q ) and E2 ( electric field for +6 Q) :