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A platinum sphere with radius 0.0197 m is totally immersed in mercury. Find the weight of...

A platinum sphere with radius 0.0197 m is totally immersed in mercury. Find the weight of the sphere, the bouyant force acting on the sphere, and the sphere's apparent weight. The densities of platinum and mercury are 2.14

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A platinum sphere with radius 1.11 cm is totally immersed in mercury. Find the weight of the sphere, the buoyant force acting on the sphere, and the sphere's apparent weight. The densities of platinum and mercury are 2.14 x 10^4 and 1.36 x 10^4, respectively.

density = mass/volume

v= volume = 4/3 *?*r^3

mass os sphere = p * 4/3 *? *r^3 = m

Weight = m*g

g=10m/s^2

Apparent weight = mg - fb

fb = buyont force

The 'thing' that is creating the bouyant force is the difference between the relative densities of the fluids hence in your case;

densities of platinum and mercury are

p= 2.14 x 10^4 and

p' = 1.36 x 10^4, respectively

fb=(p-p') * g * v

Getting fb we get Apparent weight by

Apparent weight = mg - fb

genius_generous answered 2 years ago

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