A platinum sphere with radius 0.0115 m is totally immersed in mercury. Find the weight of...

A platinum sphere with radius 0.0115 m is totally immersed in mercury. Find the weight of the sphere, the buoyant force acting on the sphere, and the sphere\'s apparent weight. The densities of platinum and mercury are 2.14

Expert Solution

Radius of sphere, r=0.0115 m

Volume of sphere, V=(4/3)*pi*r³

=(4/3)*3.14*0.0115³=6.37*10^-6 m³

Weight of sphere=Volume*density of sphere*g

=6.37*10^-6*2.14*10⁴*9.8

=1.336 N

Buoyant force= Volume*density of mercury*g

=6.37*10^-6*1.36*10⁴*9.8

=0.836 N

Apparent of sphere=Volume*(density of sphere-density of mercury)*g

=6.37*10^-6 *(2.14*10⁴-1.6*10^-4) 9.8

=1.500 N

genius_generous answered 4 months ago

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