A volleyball is spiked so that its incoming velocity of +4.1 m/s is changed to an...

A volleyball is spiked so that its incoming velocity of +4.1 m/s is changed to an outgoing velocity of -16 m/s. The mass of the volleyball is 0.34 kg. What impulse does the player apply to the ball?
____ kg·m/s

Expert Solution

Ans )By Impulse momentum theorem, Impulse = change in momentum

=> Impulse = m(v_final - v_initial)

= 0.34(-16 -4.1)

= 6.834 kg m/s (ignoring the sign)

genius_generous answered 2 years ago

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