In: Physics
An airplane is flying with a velocity of 240 m/s at an angle of 30.0° with the horizontal, as the drawing shows. When the altitude of the plane is 2.4 km, a flare is released from the plane. The flare hits the target on the ground. What is the angle θ?
It seems to behorizantal prohection of the projectile.
Horizantal component of the velocity=V0 cos theta
=240*cos (-30)
=240* 3/2
=207.846
-2400=240*sqrt(3)/2*t-(1/2)g t^2
-2400=207.85 t-0.5 t^2
-4800=415.69t-t^2
t^2-415.69t+4800=0
t=11.8869 sec
horizantal distance =Vocos theta*t= 2470.65 m
from the figure tan theta=2400/2470.65
theta =440 from the horizantal.(see figure)