Question

In: Statistics and Probability

A farmer records the number of bees spotted on his farm over a two week period...

A farmer records the number of bees spotted on his farm over a two week period in the middle of the summer. Below is a stem and leaf plot of his data:

1 67
2 269
3 29
4 399
5 4
6 14
7
8 7

key: 1 6=16

1) Find the mean, median, mode, and sample standard deviation for this data

2) List the values for your Five Number Summary for the data in order.

3) Identify any outliers using the IQR Method

4) ) If the true distribution for number of bees on the farm on a given day at this time of year is normal with a mean of 45 and a standard deviation of 15, find the z-score for a day when 32 bees are observed. Is this an unusual number of bees to see during the day at this time of year?

Solutions

Expert Solution

1.

Mean

42

Median

41

Mode

49

stdev

20.283

2.

Five number summary

minimum

16

Q1

26.75

Q2

41

Q3

52.75

Maximum

87

3.

IQR (Q3-Q1)

26

Q1-1.5*IQR

-12.25

Q3+1.5IQR

91.75

No number is < -12.25 and no number is > 91.75. Hence there are no outliers

# bees
16
17 QNo
22 Q2 Five number summary
26 minimum 16
29 Q1 26.75
32 Q2 41
39 Q3 52.75
43 Maximum 87
49
49
54 Q3 IQR (Q3-Q1) 26
61 Q1-1.5*IQR -12.25
64 Q3+1.5IQR 91.75
87
Q1 Mean 42 Q4 Z score -0.867
Median 41
Mode 49
stdev 20.283

Excle function used

orchestra answered 1 year ago
Next > < Previous

Related Solutions

Suppose a farmer is interested in developing a breeding program on his chicken farm. The farmer...
Suppose a farmer is interested in developing a breeding program on his chicken farm. The farmer would like to artificially select for egg weight, egg shape, shell color, and shell thickness. In a large population of his chickens, the farmer has measured these four continuous egg traits of interest and calculated their variances, shown in the table below. Variance Weight Shape Shell Color Shell Thickness Phenotypic 166 1043 157 176 Additice Genetic 4 140 83 22 Environmental 83 522 95.4...
Freight car loadings over an 18-week period at a busy port are as follows: Week Number...
Freight car loadings over an 18-week period at a busy port are as follows: Week Number Week Number Week Number 1 360 7 430 13 505 2 375 8 450 14 515 3 390 9 470 15 545 4 375 10 455 16 560 5 390 11 475 17 575 6 400 12 495 18 590 a. Determine a linear trend line for expected freight car loadings. YˆY^ =  +  t b. Use the above trend equation to predict expected loadings for...
Freight car loadings over an 18-week period at a busy port are as follows: Week Number...
Freight car loadings over an 18-week period at a busy port are as follows: Week Number Week Number Week Number 1 370 7 415 13 450 2 380 8 425 14 455 3 390 9 435 15 475 4 380 10 425 16 485 5 390 11 435 17 495 6 395 12 445 18 505 a. Determine a linear trend line for expected freight car loadings. (Round your intermediate calculations and final answers to 2 decimal places.) YˆY^ =  +  t...
Freight car loadings over an 18-week period at a busy port are as follows: Week Number...
Freight car loadings over an 18-week period at a busy port are as follows: Week Number Week Number Week Number 1 290 7 335 13 490 2 300 8 375 14 495 3 310 9 415 15 515 4 300 10 405 16 525 5 310 11 445 17 535 6 315 12 485 18 545 a. Determine a linear trend line for expected freight car loadings. (Round your intermediate calculations and final answers to 2 decimal places.) YˆY^ =  +  t...
The number of times a machine broke down each week was observed over a period of...
The number of times a machine broke down each week was observed over a period of 100 weeks and recorded as shown in the table below. Complete parts a and b below. Number of Breakdowns 0 1 2 3 4 5 or More Number of weeks 9 22 32 26 6 5 a. Using alphaequals?0.10, perform a? chi-square test to determine if the population distribution of breakdowns follows the Poisson probability distribution. What is the null? hypothesis, Upper H 0??...
Bob the Farmer grows vegetables at his farm in South Dakota. He grows his vegetables for...
Bob the Farmer grows vegetables at his farm in South Dakota. He grows his vegetables for sale to food companies. On November 1, he sells his vegetables to Granny’s Pie Company for $65,000, inclusive of 13% VAT. Granny’s Pie Company uses his vegetables to produce savory meat and vegetable pies (they’re huge in the UK). After the production of the pies is complete, Granny’s Pie Company sells the pies to Winn Dixie Grocery Stores for $140,000, inclusive of 13% VAT....
Bob the Farmer grows vegetables at his farm in South Dakota. He grows his vegetables for...
Bob the Farmer grows vegetables at his farm in South Dakota. He grows his vegetables for sale to food companies. On November 1, he sells his vegetables to Granny’s Pie Company for $65,000, inclusive of 13% VAT. Granny’s Pie Company uses his vegetables to produce savory meat and vegetable pies (they’re huge in the UK). After the production of the pies is complete, Granny’s Pie Company sells the pies to Winn Dixie Grocery Stores for $140,000, inclusive of 13% VAT....
A farmer is building a new machine shed on his farm. Calculate the average annual fixed...
A farmer is building a new machine shed on his farm. Calculate the average annual fixed cost for the machine shed using the information given below. The annual fixed costs or ownership costs are depreciation, interest, taxes, and insurance. Purchase price = $180,000 Salvage value = $0 Useful life = 20 years Property taxes = $5,200 Insurance = $5,500 Cost of capital = 9%
#2. Farmer Brown sold the mineral rights on his farm to Exxon Corporation in exchange for...
#2. Farmer Brown sold the mineral rights on his farm to Exxon Corporation in exchange for payments of $14,000 per year in perpetuity. Using a discount rate of 6.5 percent, compute the present value of this arrangement #3. Investment X has the following projected cash flows over the next four years: Year Amount 1 $5700 2 $4900 3 $4300 4 $2000 If the opportunity cost for an investment of this level of risk is 9.1%, what is the most that...
(10 marks) A farmer has discovered that on his farm, he can get 30 bushels of...
A farmer has discovered that on his farm, he can get 30 bushels of corn per acre if he applies no fertilizer. When he applies N pounds of fertilizer to an acre of land, the marginal product of fertilizer is 1−N/200 bushels of corn per pound of fertilizer. (a) If the price of corn is $3 a bushel and the price of fertilizer is $p per pound (where p < 3), how many pounds of fertilizer should be use per...
ADVERTISEMENT
Subjects
ADVERTISEMENT
Latest Questions
ADVERTISEMENT