Question

In: Physics

When two lenses are used in combination, the first one forms an image that then serves...

When two lenses are used in combination, the first one forms an image that then serves as the object for the second lens. The magnification of the combination is the ratio of the height of the final image to the height of the object. A 1.90 cm -tall object is 56.0 cm to the left of a converging lens of focal length 40.0 cm . A second converging lens, this one having a focal length of 60.0 cm , is located 300 cm to the right of the first lens along the same optic axis.

A. Find the location and height of the image (call it I1) formed by the lens with a focal length of 40.0 cm .


s′1|y′1| =

B. I1 is now the object for the second lens. Find the location and height of the image produced by the second lens. This is the final image produced by the combination of lenses.

s′2, |y′2| =

Solutions

Expert Solution


Related Solutions

When two lenses are used in combination, the first one forms an image that then serves...
When two lenses are used in combination, the first one forms an image that then serves as the object for the second lens. The magnification of the combination is the ratio of the height of the final image to the height of the object. A 1.80 cm -tall object is 51.0 cm to the left of a converging lens of focal length 40.0 cm . A second converging lens, this one having a focal length of 60.0 cm , is...
The figure shows a combination of two identical lenses
The figure shows a combination of two identical lenses. (Intro 1 figure) Part A Find the position of the final image of the 2.0-cm-tall object. x = ___ cm from the object.   Part B Find the size of the final image of the 2.0-cm-tall object. h =  ___ cm   Part C Find the orientation of the final image of the 2.0-cm-tall object. erect inverted  
The procedure known as ray tracing is a pictorialmethod for understanding image formation when lenses...
The procedure known as ray tracing is a pictorial method for understanding image formation when lenses or mirrors are used. It consists of locating the image by the use of just three "special rays." The following tactics box explains this procedure for the case of a converging lens.TACTICS BOX 23.2 Ray tracing for a converging lensDraw an optical axis. Use graph paper or a ruler. Establish an appropriate scale.Center the lens on the axis. Mark and label the focal points...
a) When glasses (or contact lenses) are usedto correct nearsightedness, where should the corrective lens forman image...
a) When glasses (or contact lenses) are usedto correct nearsightedness, where should the corrective lens forman image of an object located at infinity in order for the eye toform a clear image of that object? The lensshould form the image at the near point. The lensshould form the image at the far point. The lensshould form the image at a point closer to the eye than the nearpoint. The lensshould form the image at a point farther from the eye...
Two thin lenses with a focal length of magnitude 12.0cm, the first diverging and the second...
Two thin lenses with a focal length of magnitude 12.0cm, the first diverging and the second converging, are located 9.00cm apart. An object 2.50mm tall is placed 20.0cm to the left of the first (diverging) lens. Note that focal length of diverging lens is a negative number while focal length of converging lens would be positive. (a) Draw a figure showing both lenses and use principal rays to find approximate position of the image formed by the first lens. (b)...
Two lenses are separated by L = 50.0 cm. The first lens (light coming from the...
Two lenses are separated by L = 50.0 cm. The first lens (light coming from the left.) has a focal length f1 = 24.0 cm and the second lens has a focal length f2 = 18.0 cm. An object is located 40.0 cm (s1) to the left of the first lens. Calculate the position of the two images formed by the lens system. State whether each image is real or virtual. Repeat this problem with L = 10.0 cm.
Consider two Images of same dimensions where one image is an original image and other should...
Consider two Images of same dimensions where one image is an original image and other should be a degraded image.    Write a matlab program to measure picture quality using objective assessment validation criteria for the degraded image and original image. Calculate MSE, PSNR, Normalized absolute error, Maximum Difference, Structural content, Average difference, Normalized cross correlation for the images.    Explain the importance of Objective assessment in Image processing
Two lenses, one converging with focal length 22.0 cmcm and one diverging with focal length −−...
Two lenses, one converging with focal length 22.0 cmcm and one diverging with focal length −− 11.0 cmcm , are placed 25.0 cmcm apart. An object is placed 60.0 cmcm in front of the converging lens. Part A Find the final image distance from second lens. Follow the sign conventions. Express your answer to two significant figures and include the appropriate units. Part B Determine the magnification of the final image formed. Follow the sign conventions. Express your answer using...
What is the first step normally taken when you look through the ocular lenses? What does...
What is the first step normally taken when you look through the ocular lenses? What does it mean that the image is inverted when you look through the ocular lenses? What is the difference between the coarse adjustment knob and the fine adjustment knob? When is it appropriate to use them? What new details are you able to see on the slide when the magnification is increased to 10x that you could not see at 4x? What about 40x?
Create two new images by applying a threshold first to various colors in the image. In...
Create two new images by applying a threshold first to various colors in the image. In practice, applying a threshold means that you zero out (set to zero) any value above or below a specified limit. For the first image (im1mod1), zero out all pixels that are below the value 128. For the second image (im1mod2), zero out all red pixels entirely, zero out all green pixels ABOVE 128, and zero out all blue pixels BELOW 128. Use the command...
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT