Calculate the grams of K2CO3 required to prepare 510.0 mL of a 0.777 g/L K+ solution....

Calculate the grams of K₂CO₃ required to prepare 510.0 mL of a 0.777 g/L K⁺ solution. [Answer in 4 SF].

Expert Solution

0.777 g/L K⁺ solution means 0.777g of K+ present in 1L of solution

1L of solution contains 0.777g of K⁺

1000ml of solution contains 0.777g of K⁺

510ml of solution contains = 0.777*510/1000 =0.39627 g of K⁺

2*39g of K⁺ obtain from 138g of k2CO3

0.39627G OF k⁺ obtain from= 138*0.39627/2*39 = 0.701g of K2CO3

queen_honey_blossom answered 2 years ago

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