Question

In C: Write a function definition called PhoneType that takes one character argument/parameter called phone and returns a double.

When the variable argument phone contains the character a or A print the word Apple and return 1099.99

When phone contains anything else return a 0.0

Answer 1

Source code:

#include <stdio.h>

double PhoneType(char phone)
{
   double val=0.0;
   if(phone=='a' || phone=='A')
   {
       printf("Apple\n");
       val=1099.99;
   }
   else
   {
       val=0.0;
   }
   return val;
}
int main()
{
   printf("Calling with parameter 'a'\n");
   printf("%lf\n",PhoneType('a') );
   printf("\nCalling with parameter 'A'\n");
   printf("%lf\n",PhoneType('A') );
   printf("\nCalling with parameter 'z'\n");
   printf("%lf\n",PhoneType('z') );
}

Sample input and output: