The Ksp of PbI2 is 1.4 x 10-8. Calculate the molar solubility of PbI2 in 0.01...

The Ksp of PbI2 is 1.4 x 10-8. Calculate the molar solubility of PbI2 in 0.01 M NaI.

1.5 x 10-3 M

1.4 x 10-4 M

1.4 x 10-6 M

5.6 x 10-2 M

Expert Solution

answer : 1.4 x 10^-4 M

concentration of [I-] = 0.01 M

PbI2 <-------------> Pb+2 + 2 I-

S 2S

S 2S + 0.01

S 0.01

Ksp = [Pb+2][I-]^2

1.4 x 10^-8 = S x (0.01)^2

S = 1.4 x 10^-4 M

solubility of PbI2 = 1.4 x 10^-4 M

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