In: Statistics and Probability
Given μX = 8.3, σX = 3.2
a) Find Z1 such that prob(.35 < Z < Z1) = .3231
b) Find prob(-1.2 < Z < 2.7)
c) Find prob(Z = .83)
d) Find any Z0 and Z1 such that prob(Z0 < Z < Z1) = .4444
a)
P ( 0.350 < Z <
1.750 )
= P ( Z < 1.750 ) - P ( Z
< 0.350 ) =
0.9599 - 0.6368 =
0.3231
Z1 = 1.75
b)
µ = 8.3
σ = 3.2
P ( -1.200 < Z <
2.700 )
= P ( Z < 2.700 ) - P ( Z
< -1.200 ) =
0.9965 - 0.1151 =
0.8815
............
C)
so, X=zσ+µ= 0.83 *
3.2 + 8.3
X = 10.96
(answer)
d)
µ = 8.3
σ = 3.2
proportion= 0.4444
proportion left 0.5556 is equally
distributed both left and right side of normal
curve
z value at 0.2778 = ±
0.589 (excel formula =NORMSINV(
0.56 / 2 ) )
z0 = -0.589
z1 = 0.589
THANKS
revert back for doubt
please upvote