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The Bombay phenotype occurs when an individual human is homozygous for a recessive allele at the...

The Bombay phenotype occurs when an individual human is homozygous for a recessive allele at the FUT1 locus. Individuals with this genotype do not make a precursor substance required to synthesize the A and B antigens that sometimes appear on human red blood cells. Regardless of their genotype at the ABO blood type locus, individuals who are homozygous for the Bombay phenotype allele at the FUT1 locus will appear to have blood type O on standard blood type tests.

Note: There are two possible alleles at the FUT1 locus: the normal allele, symbolized as H, and the Bombay phenotype allele, symbolized as h. There are three possible alleles at the ABO blood type locus, symbolized as A, B, and O. Alleles A and B are dominant to allele O. Alleles A and B have a codominant relationship with each other.

A man who is a heterozygous carrier of the Bombay phenotype allele and has blood type AB has children with a woman who is also a heterozygous carrier of the Bombay phenotype allele and has blood type O. Write out the full genotypes (including both loci) for each of these individuals. Specify which genotype belongs to the man and which genotype belongs to the woman.

What would be the probability of the two individuals producing offspring with each of the blood types below:

A, B, AB, O

Solutions

Expert Solution

Answer –

As given, the normal allele for FUT1 locus be represented by H which is dominant over Bombay-phenotype allele be represented by h.

Let the allele for A-antigen is represented by IA and the allele for B-antigen is represented by IB while the allele for O-blood group be represented by I for ABO locus.

A person with genotype h/h will produce O-blood group regardless with the genotype at ABO locus.

A- and B- blood group will be produced only when the genotype of FUT1 locus is homozygous dominant (H/H) or heterozygous dominant (H/h).

According to the question the following cross occurs

Parent phenotype -   

Heterozygous carrier of Bombay phenotype with blood type AB, male X   Heterozygous carrier of Bombay phenotype with O blood type, female

Parent genotype                         H IA/h IB X           H i/h i

Gamete genotype                        H IA    h IB    H IB   h IA     X         H i    h i

Offspring- Punnett square

Female/male gametes

H IA

h IB

H IB

h IA

H i

H IA / H i

A-blood group

h IB/ H i

B-blood group

H IB/ H i

B-blood group

h IA/ H i

A-blood group

h i

H IA/h i

A-blood group

h IB/h i

O-blood group

H IB/h i

B-blood group

h IA/h i

O-blood group

Expected phenotype ratio – A-blood group: B-blood group: O-blood group = 3:3:2

Probability of individual with particular blood-group = Number of individuals with particular blood-group/Total number of individuals

Probability of individual with blood group

A = 3/8 X 100 = 37.5%

B = 3/8 X 100 = 37.5%

AB = 0/8 X 100 = 0%

O = 2/8 X 100 = 25%

Blood-group type

Probability (%)

A

37.5

B

37.5

O

25.0

AB

0.0

gladiator answered 2 years ago
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