In: Advanced Math
Are nursing salaries in Tampa, Florida, lower than those in Dallas, Texas? As reported by the Tampa Tribune, salary data show staff nurses in Tampa earn less than staff nurses in Dallas. Suppose that in a follow-up study of 41 staff nurses in Tampa and 51 staff nurses in Dallas you obtain the following results. Enter negative value as negative number.
Tampa | Dallas | |
---|---|---|
n1=41 | n2=51 | |
^-x1=58,800 | ^-x2=62,800 | |
s1=4,800 | s2=6,200 |
a. Formulate hypothesis so that, if the null hypothesis is rejected, we can conclude that salaries for staff nurses in Tampa are significantly lower than for those in Dallas. Use a=.05
- Select your answer -<>≤≥=≠Item 1 | ||
- Select your answer -<>≤≥=≠Item 2 |
b. What is the value of the test statistic?
(to 3 decimals)
c. What is the p-value?
Degrees of freedom is ? Round degrees of freedom to previous whole number.
Consider the following results for independent samples taken from two populations.
Sample 1 | Sample 2 |
n1 = 400 | n2= 300 |
p1= 0.49 | p2= 0.39 |
a. What is the point estimate of the difference
between the two population proportions (to 2 decimals)?
b. Develop a 90% confidence interval for the
difference between the two population proportions (to 4 decimals).
Use z-table.
? to ?
c. Develop a 95% confidence interval for the
difference between the two population proportions (to 4 decimals).
Use z-table.
? to ?
Consider the following hypothesis test.
H0: u1 - u2 ≤ 0
Ha: u1 -u 2 > 0
Consider the following results for two independent random samples taken from two populations.
Sample 1 | Sample 2 |
n 1 = 100 | n 2 = 300 |
p1 = .22 | p 2 = .11 |
Use pooled estimator of p.
Question 1
a.
Null hypothesis :
Alternative hypothesis :
b.
c.
P-value = 0.0004
Formula for degrees of freedom is :
Degrees of freedom = df = 89.891 89 ( Rounded to previous whole number.)
Question 2
a.
Point estimate of the difference between the two population proportions = p1 - p2 = 0.49 - 0.39 = 0.10
b.
90% confidence interval for the difference between the two population proportions : ( 0.0381 , 0.1619 )
c.
95% confidence interval for the difference between the two population proportions : ( 0.0262 , 0.1738 )
Question 3