Question

In the book Business Research Methods (5th ed.), Donald R. Cooper and C. William Emory discuss studying the relationship between on-the-job accidents and smoking. Cooper and Emory describe the study as follows:

Suppose a manager implementing a smoke-free workplace policy is interested in whether smoking affects worker accidents. Since the company has complete reports of on-the-job accidents, she draws a sample of names of workers who were involved in accidents during the last year. A similar sample from among workers who had no reported accidents in the last year is drawn. She interviews members of both groups to determine if they are smokers or not.

The sample results are given in the following table.

	On-the-Job Accident
Smoker	Yes		No		Row Total
Heavy	15		10		25
Moderate	8		6		14
Nonsmoker	11		16		27
Column total	34		32		66

Expected counts are below observed counts
	Accident		No Accident		Total
Heavy	15		10		25
	12.88		12.12
Moderate	8		6		14
	7.21		6.79
Nonsmoker	11		16		27
	13.91		13.09
Total	34		32		66
Chi-Sq = 2.15, DF = 2, P-Value = 0.341

(a) For each row and column total in the above table, find the corresponding row/column percentage. (Round your answers to 2 decimal places.)

Row 1	%
Row 2	%
Row 3	%
Column 1	%
Column 2	%

(b) For each cell in the above table, find the corresponding cell, row, and column percentages. (Round your answers to 2 decimal places.)

	Accident	No Accident
Heavy	Cell=  %	Cell=  %
	Row=  %	Row=  %
	Column=  %	Column=  %
Moderate	Cell=  %	Cell=  %
	Row=  %	Row=  %
	Column=  %	Column=  %
Nonsmoker	Cell=  %	Cell=  %
	Row=  %	Row=  %
	Column=  %	Column=  %

(c) Use the MINITAB output in the above to test the hypothesis that the incidence of on-the-job accidents is independent of smoking habits. Set α = .01.

(Click to select)RejectDo not reject H₀.

(d) Is there a difference in on-the-job accident occurrences between smokers and nonsmokers?

Conclude there is (Click to select)no differencedifference between smokers and nonsmokers.

Answer 1

a).

Row 1	%
Row 2	%
Row 3	%
Column 1	%
Column 2	%

b).

	accident	no accident
Heavy	Cell=  %	Cell= %
	Row= %	Row= %
	Column= %	Column= %
Moderate	Cell= %	Cell= %
	Row= %	Row= %
	Column= %	Column= %
Nonsmoker	Cell=  %	Cell= %
	Row= %	Row= %
	Column=  %	Column= %

formula used:-

cell percentage = (cell value/ total )*100

row percentage= (cell value/ row total)*100

column percentage= (cell value / column total)*100

c). p value = 0.341 >0.01 , so we do not have enough evidence to reject null hypothesis.

d). Conclude that  there is no difference between smokers and nonsmokers.

[ because we fail to reject the null hypothesis.

our hypothesis:-

H₀: there is no relationship in on the job accident occurrences between smokers and non smokers.

H₁: there is a relationship in on the job accident occurrences between smokers and non smokers.]

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