In: Statistics and Probability
Solution :
x : The annual commissions earned by sales representatives
µ = $42,000
σ = $4000
Using Normal Distribution,
a. What percent of representatives earn less than $45,000?
P(x<$45,000) = P((x-µ)/σ < (45,000-µ)/σ)
=P(z < (45,000-42000)/4000)
= P(z<0.75)
= 0.7734
Answer : 0.7734
b. What percent of representatives earn between $32,000 and $45,000?
P($32,000<x<$45,000) = P((x-µ)/σ < (45,000-µ)/σ) - P((x-µ)/σ < (32,000-µ)/σ)
=P(z < (45,000-42000)/4000) - P(z < (32,000-42000)/4000)
= P(z<0.75) - P(z<-2.50)
= 0.7734 - 0.0062
= 0.7672
Answer : 0.7672
c. How much is the annual commission for the top 15% of the sales representatives?
For top 15%,
Z = 1.04
the annual commission for the top 15% of the sales representatives = zσ + µ = 1.04*4000+42000 = 46160
Answer : 46160