What amount of HCl gas must be added to 1.00L of a buffer solution that contains...

What amount of HCl gas must be added to 1.00L of a buffer solution that contains [aceticacid]=2.0M and [acetate]=1.0M in order to produce a solution with pH= 4.19?

Expert Solution

no of moles of acetic acid = molarity * volume in L

= 2*1 = 2moles

no of moles of acetate = 1*1 = 1 moles

no of moles of HCl = x

PH = PKa + log[Acetate]/[Acetic acid]

4.19 = 4.74 + log1-x/2+x

log1-x/2+x = 4.19-4.74

log1-x/2+x = -0.55

1-x/2+x = 10^-0.55

1-x/2+x = 0.2818

1-x = 0.2818*(2+x)

x = 0.3404

no of moles of HCl = 0.3404 moles

mass of HCl = no of moles * gram molar mass

= 0.3404*36.5 = 12.4246g >>>>> answer

queen_honey_blossom answered 2 years ago

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