In: Statistics and Probability
Consider a relatively simple health insurance plan
with the following provisions. Office visits require a co-payment
of $40. Emergency room visits have a$275 co-payment. Surgical operations have a$1,300 deductible (the first$1,300 is paid out of pocket). The monthly premium is$400. During a one-year period, somebody insured by this health insurance has the expenses shown to the right. Complete parts (a) and (b) below. | Expenses | Total Cost |
---|---|---|
Feb. 18: Office visit | $150 | |
Mar. 26:Emergency room | $720 | |
Apr. 23: Office visit | $150 | |
May 14: Surgery | $7,000 | |
July 1: Office visit | $150 | |
Sept. 23: Emergency room | $840 |
a. Determine the person's health care expenses for the year with the insurance policy.
The person's health care expenses with the insurance policy are
$nothing.
(Type a whole number.)
b. Determine the person's health care expenses for the year without the insurance policy.
The person's health care expenses without the insurance policy are
$nothing.
(Type a whole number.)
(a) Money one has to pay for office visits = $40 x 3 = $120
Amount paid for emergency room is =$275 x 2 = $550
amount paid for surgery is =$1,300
Premium per month =$400
Total amount to be paid by the end of the year =$400 x 12 = $4800
So, the total amount paid is=$ (120+550+1300+4800) = $6,770
(b) Total expenses by the end of an year=$(150+720+150+7000+150+840) = $9,010