Question

In: Physics

A communications satellite is in a synchronous orbit that is 3.61×107 m directly above the equator....

A communications satellite is in a synchronous orbit that is 3.61×107 m directly above the equator. The satellite is located midway between Quito, Equador, and Belem, Brazil, two cities almost on the equator that are separated by a distance of 3.87×106 m. Calculate the time it takes for a telephone call to go by way of satellite between these cities. Ignore the curvature of the earth.

Solutions

Expert Solution

The total distance traveled by signal is s.
So that the distance between Belem (or Quito) to satellite iss / 2 .
Therefore we can write
    s / 2 = √ [ (h)2 + (d / 2)2 ]
                             = √ [ (3.61 x 107)2 + (3.87x 106 / 2)2 ]
                             = 3.615 x 107 m
        ==>       s = 7.23 x107 m
The time taken by electromagnetic wave to travel a totaldistance s is
                  t = s / c
                    = 7.23 x 107 / 3 x 108
    = 0.241 sec


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