Question

C++ Programm

Automobile Insurance Program:

Writes a program that prints the insurance fee to pay for a Vehicle according to the following rules:

• A Honda that is All Wheel Drive costs $450.

• A Honda that is two wheels drive costs $350.

• A Toyota that is All Wheel Drive costs $300.

• A Toyota that is Two Wheel Drive costs $250.

• A Nissan that is All Wheel Drive costs $200.

• A Nissan that is Two Wheel Drive costs $280

  Any other type of vehicle generates an error message. The program should prompt the user for the appropriate information, using a code to determine the kind of Vehicle (i.e. H or h represents a Honda, T or t represents a Toyota, N or n represents Nissan. And y or n for the AWD).

  After printing the insurance fee, the program should ask the user if (s) he wants to ensure another Vehicle using repetition structure.

  Solution Source Code C++:

Answer 1

C++ Code:

#include

#include

using namespace std;

int main() {

char ch,ch1,ch2;

int cost;

cout<<"Enter Vehicle type:\n(H/h) for Honda\n(T/t) represents Toyota\n(N/n) for Nissan:\n ";

cin>>ch;

switch(ch){

case 'H':

case 'h':

cout<<"Is it AWD :(Y/N)";

cin>>ch1;

if(ch1=='Y'||ch1=='y')

cost=450;

else

cost=350;

break;

case 'T':

case 't':

cout<<"Is it AWD :(Y/N)";

cin>>ch1;

if(ch1=='Y'||ch1=='y')

cost=300;

else

cost=250;

break;

case 'N':

case 'n':

cout<<"Is it AWD :(Y/N)";

cin>>ch1;

if(ch1=='Y'||ch1=='y')

cost=200;

else

cost=280;

break;

default:

cout<<"Wrong choice";

}

cout<<"The insurance cost is $"<

cout<<"Do you wish to check for another vehicle(Y/N): ";

cin>>ch2;

if(ch2=='Y'||ch2=='y')

main();

else

exit(0);

}