Question

In: Statistics and Probability

It has been claimed that the best predictor of today’s weather is today’s weather. Suppose that...

It has been claimed that the best predictor of today’s weather is today’s weather. Suppose that in the town of Octapa, if it rained yesterday, then there is a 60% chance of rain today, and if it did not rain yesterday there is an 85% chance of no rain today.
a) Find the transition matrix describing the rain probabilities.
b) If it rained Monday, what is the probability it will rain on Wednesday?
c) If it did not rain Friday, what is the probability of rain on Monday?
d) Using the transition matrix from part a, find the steady-state vector. Use this to determine the probability that it will be raining at the end of time.

Solutions

Expert Solution

ANSWER

------------------------------------

DEAR STUDENT,

IF YOU HAVE ANY QUERY ASK ME IN THE COMMENT BOX,I AM HERE TO HELPS YOU.PLEASE GIVE ME POSITIVE RATINGS

*****************THANK YOU***************


Related Solutions

It has been claimed that, for a penny minted in 1999 or earlier, the probability of...
It has been claimed that, for a penny minted in 1999 or earlier, the probability of observing heads upon spin- ning the penny is p = 0.30. Three students got together, and they would each spin a penny and record the num- ber X of heads out of the three spins. They repeated this experiment n = 200 times, observing 0, 1, 2, and 3 heads 57, 95, 38, and 10 times, respectively. You have n = 200 data points:...
Why there is weather on Earth rates for best explanatory answer!
Why there is weather on Earth rates for best explanatory answer!
It has been claimed that the mean armspan of adults in the US is 174 cm....
It has been claimed that the mean armspan of adults in the US is 174 cm. Does the data of our statistics class support or contradict this claim? Justify your answer through a formal hypothesis testing procedure with a P-value approach using a significance level of your choice. Calculation of and interpretation based on the P-value is required in this problem. H0: µ=174 H1: µ≠174 Sample's Mean (x-bar): 171.6 Sample's S.D. (s): 14.11743539 Sample's Test Statistic: -1.476354886 P-value: 0.072045781 CONCLUSION:...
Suppose today’s headline is that private investment has decreased as a result of actions by the...
Suppose today’s headline is that private investment has decreased as a result of actions by the Federal Reserve. Which of the following choices is the most likely cause? Selling Treasury bonds to commercial banks Lowering the discount rate Decreasing the reserve ratio Eliminating a corporate tax credit on investment A stronger stock market increased investor optimism
The regression equation is always the best predictor of a y-value for a given value of...
The regression equation is always the best predictor of a y-value for a given value of x. Defend your answer.
When the market is as volatile as it is during today’s times, what is the best...
When the market is as volatile as it is during today’s times, what is the best way to evaluate a company against the market?
Cloud seeding has been studied for many decades as a weather modification procedure. The rainfall in...
Cloud seeding has been studied for many decades as a weather modification procedure. The rainfall in acre-feet from 20 clouds that were selected at random and seeded with Silver Nitrate follows: 18.0        30.7        19.8        27.1        22.3        18.8        31.8        23.4        21.2        27.9        31.9        27.1        25.0        24.7        26.9        21.8        29.2        34.8        26.7        31.6        We need to test if the true mean rainfall exceeds 25 acre-feet. a. Write down the null and alternative hypotheses to be tested. Clearly define the terms used. b....
Cloud seeding has been studied for many decades as a weather modification procedure (for an interesting...
Cloud seeding has been studied for many decades as a weather modification procedure (for an interesting study of this subject, see the article in Technometrics, “A Bayesian Analysis of a Multiplicative Treatment Effect in Weather Modification,” Vol. 17, pp. 161–166). The rainfall in acre-feet from 18 clouds that were selected at random and seeded with silver nitrate follows: 18.0, 30.7, 19.8, 27.1, 22.3, 18.8, 31.8, 23.4, 21.2, 27.9, 31.9, 27.1, 25.0, 24.7, 26.9, 21.8, 29.2, and 34.8. (a) Can you...
Cloud seeding has been studied for many decades as a weather modification procedure (for an interesting...
Cloud seeding has been studied for many decades as a weather modification procedure (for an interesting study of this subject, see the article in Technometrics, "A Bayesian Analysis of a Multiplicative Treatment Effect in Weather Modification", Vol. 17, pp. 161–166). The rainfall in acre-feet from 20 clouds that were selected at random and seeded with silver nitrate follows: 19.0, 31.7, 20.8, 28.1, 23.3, 19.8, 32.8, 24.4, 22.2, 28.9, 32.9, 28.1, 26.0, 25.7, 27.9, 22.8, 30.2, 35.8, 27.7, 32.6 (a) Can...
Cloud seeding has been studied for many decades as a weather modification procedure. The rainfall in...
Cloud seeding has been studied for many decades as a weather modification procedure. The rainfall in acre feet from 20 clouds that were selected at random and seeded with silver nitrate follows: 18.0, 30.7, 19.8, 27.1, 22.3, 18.8, 31.8, 23.4, 21.2, 27.9, 31.9, 27.1, 25.0, 24.7, 26.9, 21.8, 29.2, 34.8, 26.7, 31.6 a) Is there evidence that the mean rainfall from seeded clouds exceeds 25 acre-feet? (1 pt) b) If the true mean rainfall is 27 acre-feet, what is the...
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT