Question

In: Advanced Math

If T1 , T2 : Rn → Rm are linear maps with range(T1) = range(T2), show...

If T1 , T2 : Rn → Rm are linear maps with range(T1) = range(T2), show that there exists an invertible linear map U:Rn →Rn so that T1=U◦T2

Solutions

Expert Solution

be two linear transformation with range (T1) = range(T2) .

Let { v1 , v2 ,...,vm } be a basis of range(T1) .

There exist { u1 , u2 , ... ,um} and{ w1 , w2 , ... ,wm} such that

T1( u1 ) = v1 , T2( w1) = v1

T1( u2) = v2 , T2 ( w2 ) = v2

..................

Tm( um ) = vm , Tm( wm ) = vm .

Since { v1 , v2 ,...,vm } be a basis of range(T1) so { u1 , u2 , ... ,um} and { w1 , w2 , ... ,wm} are also linearly independent because image of linearly dependent set is linearly dependent .

Now since { u1 , u2 , ... ,um} and { w1 , w2 , ... ,wm} are linearly independent so they can be extend to a basis of .

Let { u1 , u2 , ... ,um , um+1 ,..., un } and { w1 , w2 , ... ,wm , wm+1 , ...,wn } are basis of .

Define , is defined by ,

U(ui ) = wi for all i = 1,2 ,...,n

Then


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