Question
In: Physics
An engineer has three different capacitors of unknown capacitance. She labels them C1, C2, and C3....
An engineer has three different capacitors of unknown capacitance. She labels them C1, C2, and C3. First, she connects C1 to a battery, and the charge on C1 is q1 = 30.4 µC. Then, she disconnects and discharges C1, and connects it in series with C2. When she connects this series combination of C2 and C1 across the battery, the charge on C1 is q2 = 23.3 µC. The engineer disconnects the circuit and discharges both capacitors. Next, she connects C3, C1, and the battery in series, which results in a charge on C1 of q3 = 26.8 µC. If, after being disconnected and discharged, she connects C1, C2, and C3 in series with the battery, what is the charge on C1 (in µC)?
Solutions
genius_generous answered 2 years agoRelated Solutions
You have three capacitors: C1 = 1500. μF, C2 = 2400. μF, and C3 = 3600....
You have three capacitors: C1 = 1500. μF, C2 = 2400. μF, and C3
= 3600. μF. Find Ceq for a) all in series b) all in parallel c) c1
and c2 are in parallel and c3 in series with them d) c2 and c3 in
parallel and R1 in series with them, e)c1 and c3 in parallel and c2
in series with them. f) For one of the three arrangements where
only two of the caps are connected in...
Calculate the values "c1, c2, c3, c4, c5" with superposition 6(c1) – (c3)=50 -3(c1) + 3(c2)=0...
Calculate the values "c1, c2, c3, c4, c5" with
superposition
6(c1) – (c3)=50
-3(c1) + 3(c2)=0
9(c3) – (c2)= 160
-(c2) – 8(c3) – 2(c5) + 11(c4)=60
-3(c1) – (c2) + 4(c5)=10
Consider the combination of capacitors shown in the diagram, where C1 = 3.00uF , C2 = 11.0uF , C3 = 3.00uF , and C4 = 5.00uF .
Consider the combination of capacitors shown in the diagram, where C1 = 3.00uF , C2 = 11.0uF , C3 = 3.00uF , and C4 = 5.00uF .
Find the equivalent capacitance CA of the network of capacitors.
Express your answer in microfarads.
U(C1, C2, C3, C4, C5) = C1∙C2∙C3∙C4∙C5 As a mathematical function, does U have a maximum...
U(C1, C2, C3, C4, C5) = C1∙C2∙C3∙C4∙C5
As a mathematical function, does U have a maximum or minimum
value? What values of Ci correspond to the minimum value of U? What
values of Ci correspond to the maximum value of U? Do these values
of Ci make sense from an economic standpoint?
Now let us connect the idea of economic utility to actual dollar
values. To keep the values more manageable, we will use household
income rather than the entire...
U(C1, C2, C3, C4, C5) = C1∙C2∙C3∙C4∙C5 As a mathematical function, does U have a maximum...
U(C1, C2, C3, C4, C5) = C1∙C2∙C3∙C4∙C5
As a mathematical function, does U have a maximum or minimum
value? What values of Ci correspond to the minimum value of U? What
values of Ci correspond to the maximum value of U? Do these values
of Ci make sense from an economic standpoint?
Now let us connect the idea of economic utility to actual dollar
values. To keep the values more manageable, we will use household
income rather than the entire...
Two separate capacitors, C1 and C2 C1 = 36 micro-Coulomb on 3 micro-Farad C2 = 72...
Two separate capacitors, C1 and C2
C1 = 36 micro-Coulomb on 3 micro-Farad
C2 = 72 uC on X 2uF, , if zero 1
C2 had a gap of 0.2m maintained by a compressed plastic spring
inside the gap, the natural spring length
was 0.5m, the compressed spring length was 0.2 m. Spring constant =
8,000 micro-Newton/ meter
Action: Connected the two capacitors in parallel
Part A
Find Q2-new, C2-new, new gap,
Hint: Capacitance has geometry parameters, build an equation...
Two separate capacitors, C1 and C2 C1 = 36 micro-Coulomb on 3 micro-Farad C2 = 72...
Two separate capacitors, C1 and C2
C1 = 36 micro-Coulomb on 3 micro-Farad
C2 = 72 uC on 5 uF
C2 had a gap of 0.2m maintained by a compressed plastic spring
inside the gap, the natural spring length was 0.5m, the compressed
spring length was 0.2 m. Spring constant = 8,000 micro-Newton/
meter Action: Connected the two capacitors in parallel
Part A Find Q2-new, C2-new, new gap,
Part B Find the initial total energy, the final total energy
-use...
A capacitance C1 = 7.0x10^-6F is connected in series with a capacitance C2 = 4.0x10^-6 F,...
A capacitance C1 = 7.0x10^-6F is connected in series with a
capacitance C2 = 4.0x10^-6 F, and a potential difference of 275 V
is applied across the pair. Calculate the equivalent capacitance.
Incorrect. Tries 3/5 Previous Tries What is the charge on C1? Tries
0/5 What is the charge on C2? Tries 0/5 What is the potential
difference across C1? Tries 0/5 What is the potential difference
across C2? Tries 0/5 (c25p72) Repeat for the same two capacitors
but with...
. If it has the following solution: y= c1 + c2 cos (2x) + c3 sin...
.
If it has the following solution:
y= c1 + c2 cos (2x) + c3 sin
(2x) + c4 e3x
Then:
Two capacitors, C1=7500pF and C2=2900pF, are connected in series to a 15.0 V battery. The capacitors...
Two capacitors, C1=7500pF and C2=2900pF, are connected in series
to a 15.0 V battery. The capacitors are later disconnected from the
battery and connected directly to each other, positive plate to
positive plate, and negative plate to negative plate.
What then will be the charge on each capacitor?
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