Question

In: Statistics and Probability

You must estimate the mean temperature (in degrees Fahrenheit) with the following sample temperatures: You must...

You must estimate the mean temperature (in degrees Fahrenheit) with the following sample temperatures:

You must estimate the mean temperature (in degrees Fahrenheit) with the following sample temperatures:
72.8
58.8
56.2
66.2
74.1


Find the 99% confidence interval. Enter your answer as an open-interval (i.e., parentheses) accurate to two decimal places (because the sample data are reported accurate to one decimal place).

99% C.I. =

Answer should be obtained without any preliminary rounding.


Find the 99% confidence interval. Enter your answer as an open-interval (i.e., parentheses) accurate to two decimal places (because the sample data are reported accurate to one decimal place).

99% C.I. =

Answer should be obtained without any preliminary rounding.

Solutions

Expert Solution

Sample Mean and Standard Devation is calculated using MS Excel as follows:

99% Confidence Interval Calculation

99% C.I. = (49.05, 82.19)


Related Solutions

You must estimate the mean temperature (in degrees Fahrenheit) with the following sample temperatures: 84.6 81.1...
You must estimate the mean temperature (in degrees Fahrenheit) with the following sample temperatures: 84.6 81.1 95.7 65.5 90.8 80.6 Find the 90% confidence interval. Enter your answer as an open-interval (i.e., parentheses) accurate to two decimal places (because the sample data are reported accurate to one decimal place). 90% C.I. =  
You must estimate the mean temperature (in degrees Fahrenheit) with the following sample temperatures: 62.4 102.8...
You must estimate the mean temperature (in degrees Fahrenheit) with the following sample temperatures: 62.4 102.8 79.9 52.7 45.5 70.6 76.2 102.3 62.4 Find the 98% confidence interval. Enter your answer as an open-interval (i.e., parentheses) accurate to two decimal places (because the sample data are reported accurate to one decimal place). 98% C.I. = Answer should be obtained without any preliminary rounding.
You must estimate the mean temperature (in degrees Fahrenheit) with the following sample temperatures: 78.1 70.7...
You must estimate the mean temperature (in degrees Fahrenheit) with the following sample temperatures: 78.1 70.7 73.8 80.1 63.1 66.8 69 78.1 66.4 76.5 70.7 68.5 Find the 99% confidence interval. Enter your answer as an open-interval (i.e., parentheses) accurate to two decimal places. Use (lower, upper) formats. 99% C.I. =
You must estimate the mean temperature (in degrees Fahrenheit) with the following sample temperatures: 45.6 36.2...
You must estimate the mean temperature (in degrees Fahrenheit) with the following sample temperatures: 45.6 36.2 32.9 21.8 31.5 29.2 30 37.9 24.1 26.9 Find the 98% confidence interval. Enter your answer as an open-interval (i.e., parentheses) accurate to two decimal places (because the sample data are reported accurate to one decimal place). 98% C.I. = Answer should be obtained without any preliminary rounding.
You must estimate the mean temperature (in degrees Fahrenheit) with the following sample temperatures: 26.6 58.4...
You must estimate the mean temperature (in degrees Fahrenheit) with the following sample temperatures: 26.6 58.4 47.5 62.2 33 49.3 40.3 Find the 98% confidence interval. Enter your answer as an open-interval (i.e., parentheses) accurate to two decimal places (because the sample data are reported accurate to one decimal place). 98% C.I. = Answer should be obtained without any preliminary rounding.
You must estimate the mean temperature (in degrees Fahrenheit) with the following sample temperatures: 33 46.8...
You must estimate the mean temperature (in degrees Fahrenheit) with the following sample temperatures: 33 46.8 41.8 33.4 39.5 33 44.5 34 Find the 99% confidence interval. Enter your answer as an open-interval (i.e., parentheses) accurate to two decimal places (because the sample data are reported accurate to one decimal place). 99% C.I. =
The following data show the body temperatures (in degrees Fahrenheit) from a random sample of 12...
The following data show the body temperatures (in degrees Fahrenheit) from a random sample of 12 independent healthy people in the United States. 98.5 98.2 99.1 96.6 98.1 98.7 97.5 99.0 97.4 98.3 97.8 98.2 What would be the estimate of the average body temperature of healthy people in the United States. Find a 95% confidence interval for the average body temperature of healthy people in the United States. Explain carefully the interval you found in part (b) means. can...
The body temperatures in degrees Fahrenheit of a sample of adults in one small town are:...
The body temperatures in degrees Fahrenheit of a sample of adults in one small town are: 99.3 99.1 97.6 97.4 97.9 97.1 97.2 Assume body temperatures of adults are normally distributed. Based on this data, find the 99% confidence interval of the mean body temperature of adults in the town. Enter your answer as an open-interval (i.e., parentheses) accurate to 3 decimal places. Assume the data is from a normally distributed population. 99% C.I. =    
The body temperatures in degrees Fahrenheit of a sample of adults in one small town are:...
The body temperatures in degrees Fahrenheit of a sample of adults in one small town are: 96.8 98.3 99.6 96.7 97.1 97.5 97 99.5 99 99.2 98.4 Assume body temperatures of adults are normally distributed. Based on this data, find the 95% confidence interval of the mean body temperature of adults in the town. Enter your answer as an open-interval (i.e., parentheses) accurate to 3 decimal places. Assume the data is from a normally distributed population. 95% C.I. =
The body temperatures in degrees Fahrenheit of a sample of adults in one small town are:...
The body temperatures in degrees Fahrenheit of a sample of adults in one small town are: 98.7 97.9 98.6 99 98.1 98 96.5 99.1 99.6 97 99.3 Assume body temperatures of adults are normally distributed. Based on this data, find the 90% confidence interval of the mean body temperature of adults in the town. Enter your answer as an open-interval (i.e., parentheses) accurate to 3 decimal places. Assume the data is from a normally distributed population. 90% C.I. =
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT