Question

In: Chemistry

The decomposition of XY is second order in XYand has a rate constant of 6.92×10−3 M−1⋅s−1at...

The decomposition of XY is second order in XYand has a rate constant of 6.92×10−3 M−1⋅s−1at a certain temperature.

Part A

What is the half-life for this reaction at an initial concentration of 0.100 M?

t1/2 =

.0125

  s  

Part B

How long will it take for the concentration of XY to decrease to 12.5% of its initial concentration when the initial concentration is 0.100 M?

t =   s  

Part C

How long will it take for the concentration of XY to decrease to 12.5% of its initial concentration when the initial concentration is 0.200 M?

t = ________ s  

Part D

If the initial concentration of XY is 0.160 M , how long will it take for the concentration to decrease to 6.80×10−2 M ?

Express your answer using two significant figures.

t = _______   s  

Part E

If the initial concentration of XY is 0.050 M, what is the concentration of XY after 55.0 s ?

Express your answer using two significant figures.

[XY]t = ______   M  

Part F

If the initial concentration of XY is 0.050 M, what is the concentration of XY after 600 s ?

Express your answer using two significant figures.

[XY]t = _______   M  

Please explain and show work with the answers, I have been struggling for the past hour trying to solve the problem!!! Thanks for your help

Solutions

Expert Solution

a)

  1. We know that for second order reaction the half life will be

Part B

How long will it take for the concentration of XY to decrease to 12.5% of its initial concentration when the initial concentration is 0.100 M?

Answer: Let initial concentration =[A0] = 0.10 then [At] = 0.125 [A0] = 0.125 X 0.1 = 0.0125 M

0.00692 X t

time = 10115.61 seconds

Part C

How long will it take for the concentration of XY to decrease to 12.5% of its initial concentration when the initial concentration is 0.200 M?

40 = 5 + 0.00692 t

t = 5057.81 seconds = 5.1 X 103 seconds

D) If the initial concentration of XY is 0.160 M , how long will it take for the concentration to decrease to 6.80×10−2 M ?

At = 0.068 M A0 = 0.160 k = 0.00692

time = 1222.54 seconds = 1.2 X 103 seconds

E) If the initial concentration of XY is 0.050 M, what is the concentration of XY after 55.0 s

A0 = 0.050 t = 55 s K = 0.00692

At = 0.0491 M = 0.049 M

Part F

If the initial concentration of XY is 0.050 M, what is the concentration of XY after 600 s ?

A0 = 0.050 t = 600 s K = 0.00692

At = 0.041 M


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