In: Statistics and Probability
Motorcycles with a certain type of mileage that're normally distributed with a mean of 23.9 mpg with a standard deviation of 1.2 mpg. If 13 motorcycles of this type are randomly selected, find the probability that their average mileage is between 24 and 26 mpg.
Solution :
Given that ,
mean = = 23.9
standard deviation = = 1.2
n = 13
= 23.9
= / n= 1.2 / 13=0.3328
P(24< <26 ) = P[(24-23.9) / 0.3328 < ( - ) / < (26-23.9) /0.3328 )]
= P(0.30 < Z < 6.31)
= P(Z <631 ) - P(Z <0.30 )
Using z table
=1-0.6179
=0.3821
probability= 0.3821