In: Statistics and Probability
Benjamin owns a small Internet business. Besides himself, he employs nine other people. The salaries earned by the employees are given below in thousands of dollars (Benjamin's salary is the largest, of course). Complete parts (a) through (d) below. 10, 30, 45, 50, 50, 55, 55, 55, 60, 80
(a) Determine the mean, median, and mode for salary.
The mean salary is -----thousand dollars.
(Type an integer or a decimal. Do not round.)
The median salary is----- thousand dollars.
(Type an integer or a decimal. Do not round.)
Select the correct choice below and fill in any answer boxes in your choice.
A. The mode salary is ----- thousand dollars.
(b) The business has been good! As a result, Benjamin has a total of $24,500 in bonus pay to distribute to his employees. One option for distributing bonuses is to give each employee (including himself) $2,450 Add the bonuses under this plan to the original salaries to create a new data set. Recalculate the mean, median, and mode. How do they compare to the originals?
mean for the new data set--- thousand
median---- thousand
mode ---- thousand
How do the mean, median, and mode compare to the originals?
A.The mean increased by
$2 comma 4502,450,
but the median and the mode did not change.
B.
All three measures increased by 10%.
C.All three measures increased by
$2 comma 4502,450.
D.
The mean, median, and mode did not change.
(a) Determine the mean, median, and mode for salary.
x | |
1 | 10,000 |
2 | 30,000 |
3 | 45,000 |
4 | 50,000 |
5 | 50,000 |
6 | 55,000 |
7 | 55,000 |
8 | 55,000 |
9 | 60,000 |
10 | 80,000 |
Total | 490,000 |
Mean = Sum / n
= 490,000 / 10
= 49,000
The mean salary is 49 thousand dollars.
Median = (N + 1) /2 th value
= 5.5th value
= 5th + 0.5(6th - 5th)
= 50 + 0.5 *(55 - 50)
= 52.5
The median salary is 52.5 thousand dollars.
Mode is the value with the highest frequency. Here since 55 is repeated the most so
The mode salary is 55 thousand dollars.
(b) The business has been good! As a result, Benjamin has a total of $24,500 in bonus pay to distribute to his employees. One option for distributing bonuses is to give each employee (including himself) $2,450 Add the bonuses under this plan to the original salaries to create a new data set. Recalculate the mean, median, and mode. How do they compare to the originals?
New X | |
1 | 12,450 |
2 | 32,450 |
3 | 47,450 |
4 | 52,450 |
5 | 52,450 |
6 | 57,450 |
7 | 57,450 |
8 | 57,450 |
9 | 62,450 |
10 | 82,450 |
Total | 514,500 |
Mean = 514500 / 10
= 51450
mean for the new data set 51.45 thousand (49+2.45)
we notice that if the same amount is added to all the values then there is a same absolute increase in the mean as well. Here we are using the entire data set.
Median = 5.5th value
= 54,950
median 54.95 thousand (52.5 + 2.45)
Here unlike mean we use only 1 or 2 values. So if the increase is same for all the rank will remain the same. Therefore the new median will increase too by same amount in absolute terms.
The value of 57450 is repeated highest.
mode 57.45 thousand (55 + 2.45)
Like median mode is only affected by one value if the number of frequency changes then it will change. Since same amount is added there is no change the frequencies. So it has same absolute change.
How do the mean, median, and mode compare to the originals?
C.All three measures increased by $2,450.
Please give it a thumps up if the solution helped you.