Question

In: Statistics and Probability

The average length of a maternity stay in a U.S. hospital is 2.2 days with a...

The average length of a maternity stay in a U.S. hospital is 2.2 days with a standard deviation of 0.6 days. A sample of 25 women who recently gave birth is taken. Find the probability that the sample mean is greater than 2.4 days. Round your answer to the nearest hundredth.

Solutions

Expert Solution

Solution :

Given that,

mean = = 2.2

standard deviation = = 0.6

n=25

= =2.2

= / n = 0.6 / 25 = 0.12

P( > 2.4) = 1 - P( <2.4 )

= 1 - P[( - ) / < (2.4-2.2) /0.12 ]

= 1 - P(z < 1.67)

Using z table

= 1 - 0.9525

probability=  0.0475=0.048


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