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In: Statistics and Probability

The average length of a maternity stay in a U.S. hospital is 2.2 days with a...

The average length of a maternity stay in a U.S. hospital is 2.2 days with a standard deviation of 0.6 days. A sample of 25 women who recently gave birth is taken. Find the probability that the sample mean is greater than 2.4 days. Round your answer to the nearest hundredth.

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Expert Solution

Solution :

Given that,

mean = = 2.2

standard deviation = = 0.6

n=25

= =2.2

= / n = 0.6 / 25 = 0.12

P( > 2.4) = 1 - P( <2.4 )

= 1 - P[( - ) / < (2.4-2.2) /0.12 ]

= 1 - P(z < 1.67)

Using z table

= 1 - 0.9525

probability=  0.0475=0.048

orchestra answered 2 years ago
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