Question
In: Statistics and Probability
The average length of a maternity stay in a U.S. hospital is 2.2 days with a...
The average length of a maternity stay in a U.S. hospital is 2.2 days with a standard deviation of 0.6 days. A sample of 25 women who recently gave birth is taken. Find the probability that the sample mean is greater than 2.4 days. Round your answer to the nearest hundredth.
Solutions
Expert Solution
Solution :
Given that,
mean = 
= 2.2
standard deviation = 
= 0.6
n=25
=
=2.2
=
/ 
n = 0.6 / 25 = 0.12
P( > 2.4) = 1 - P(
<2.4 )
= 1 - P[(
-
) /
< (2.4-2.2) /0.12 ]
= 1 - P(z < 1.67)
Using z table
= 1 - 0.9525
probability= 0.0475=0.048
orchestra answered 2 years agoRelated Solutions
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