Question
In: Statistics and Probability
A manufacturer of insulation randomly selects 20 winter days and records the daily high temperature as...
A manufacturer of insulation randomly selects 20 winter days and records the daily high temperature as follows: 58,61,63,64,66,67,68,69,70,75, 76,77,77,78,79,81,82,86,85,87,88,92,93,94,99. Use as a first class 58 – 63.
|
a. |
Construct a relative frequency distribution. |
|
b. |
Construct a cumulative frequency distribution. |
|
c. |
Construct a cumulative relative frequency distribution. |
Solutions
Expert Solution
Solution-
from data provided frequency distribution is calculated-
● Relative Frequency = Frequency / Total Frequency.
● Cumulative Frequency -
The cumulative frequency is calculated by adding each frequency from a frequency distribution table to the sum of its predecessors. The last value will always be equal to the total for all observations, since all frequencies will already have been added to the previous total
● Relative Cumulative Frequency-
The Relative cumulative frequency is calculated by adding each Relative frequency from a Relative frequency distribution Column to the sum of its predecessors.
◆ descriptive measures-
orchestra answered 2 years agoRelated Solutions
A manufacturer of insulation randomly selects 20 winter days and records the daily high temperature as...
A manufacturer of insulation randomly selects 20 winter days and
records the daily high temperature as follows:
58,61,63,64,66,67,68,69,70,75,
76,77,77,78,79,81,82,86,85,87,88,92,93,94,99. Use as a first class
58 – 63.
a.
Construct a relative frequency distribution.
b.
Construct a cumulative frequency distribution.
c.
Construct a cumulative relative frequency distribution.
A call center randomly selects and records customer calls. Call handling times in minutes for 20...
A call center randomly selects and records customer calls. Call
handling times in minutes for 20 calls are as follows: 6, 26, 8, 2,
6, 3, 10, 14, 4, 5, 3, 17, 9, 8, 9, 5, 3, 28, 21, and 4. Please
calculate the 10th quartile, 90th quartile, median, Q1, Q3, sample
mean, and sample standard deviation of call handling times.
A researcher randomly selects 6 fathers who have adult sons and records the fathers' and sons'...
A researcher randomly selects 6 fathers who have adult sons and
records the fathers' and sons' heights to obtain the data shown
in the table below. Test the claim that sons are taller than their
fathers at the alpha equals 0.10α=0.10 level of significance. The
normal probability plot and boxplot indicate that the differences
are approximately normally distributed with no outliers so the use
of a paired t-test is reasonable
67.5
72.9
68.4
71.2
67.7
66.8
71.1
71.3
67.6
74.7...
A researcher randomly selects 6 fathers who have adult sons and records the fathers' and sons'...
A researcher randomly selects 6 fathers who have adult sons and
records the fathers' and sons' heights to obtain the data shown
in the table below. Test the claim that sons are taller than their
fathers at the
α=0.10
level of significance. The normal probability plot and boxplot
indicate that the differences are approximately normally
distributed with no outliers so the use of a paired t-test is
reasonable.
Observation
1
2
3
4
5
6
Height of father (in inches)...
Suppose that National Motors randomly selects a sample of n = 91 ZX-900s. The company records...
Suppose that National Motors randomly selects a sample of n = 91
ZX-900s. The company records the stopping distance of each of these
automobiles and calculates the mean and standard deviation of the
sample of n = 81 stopping distances to be ȳ = 57.8feet and s =
6.02feet.
1. Conduct hypothesis test
H0 :μ=60, Ha :μ<60.
Set α = 0.5. And calculate the p-value.
Police records show the following numbers of daily crime reports for a sample of days during...
Police records show the following numbers of daily crime reports
for a sample of days during the winter months and a sample of days
during the summer months.
Winter
Summer
16
26
20
16
15
23
18
32
21
16
20
27
12
24
18
36
17
26
20
16
Use a 0.05 level of significance to determine whether there is a
significant difference between the winter and summer months in
terms of the number of crime reports.
State the...
Police records show the following numbers of daily crime reports for a sample of days during...
Police records show the following numbers of daily crime reports
for a sample of days during the winter months and a sample of days
during the summer months.
Winter
Summer
17
27
20
17
15
21
16
34
23
17
20
28
14
22
16
37
18
27
20
17
Use a 0.05 level of significance to determine whether there is a
significant difference between the winter and summer months in
terms of the number of crime reports.
State the...
A manufacturer of nickel-hydrogen batteries randomly selects 100 nickel plates for test cells, cycles them a...
A manufacturer of nickel-hydrogen batteries randomly selects 100
nickel plates for test cells, cycles them a specified number of
times, and determines that 14 of the plates have blistered. If it
is really the case that 15% of all plates blister under these
circumstances and a sample size of 100 is used, how likely is it
that the null hypothesis of part (a) will not be rejected (to 4
decimal places). (The probability of making a type 2 error when...
A manufacturer of nickel-hydrogen batteries randomly selects 100 nickel plates for test cells, cycles them a...
A manufacturer of nickel-hydrogen batteries randomly selects 100
nickel plates for test cells, cycles them a specified number of
times, and determines that 14 of the plates have blistered.
(a) Does this provide compelling evidence for concluding that
more than 10% of all plates blister under such circumstances?
State and test the appropriate hypotheses using a significance
level of 0.05.
H0: p = 0.10
Ha: p < 0.10H0:
p = 0.10
Ha: p >
0.10 H0:
p > 0.10
Ha: p...
A manufacturer of nickel-hydrogen batteries randomly selects 100 nickel plates for test cells, cycles them a...
A manufacturer of nickel-hydrogen batteries randomly selects 100
nickel plates for test cells, cycles them a specified number of
times, and determines that 14 of the plates have blistered.
z = 1.33
p- value = 0.0913
(b) If it is really the case that 16% of all plates blister
under these circumstances and a sample size 100 is used, how likely
is it that the null hypothesis of part (a) will not be rejected by
the 0.05 test? (Round your...
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