In: Advanced Math
A coffee company uses a data-based approach to improving the quality and customer satisfaction of its products. When survey data indicated that the coffee company needed to improve its package-sealing process, an experiment was conducted to determine the factors in the bag-sealing equipment that might be affecting the ease of opening the bag without tearing the inner liner of the bag. One factor that could affect the rating of the ability of the bag to resist tears was the plate gap on the bag-sealing equipment. Data were collected on 19 bags in which the plate gap was varied. Complete parts (a) through (e) below.
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a. Construct a scatter plot. Choose the correct graph below.
A.
-15-15Tear RatingPlate Gap
Edit Coordinates(0,0)
A scatter plot has a horizontal axis labeled Tear Rating from negative 1 to 5 to in increments of 1 and a vertical axis labeled Plate Gap from negative 2 to 5 in increments of 1. A series of plotted points range from horizontal coordinates 0.0 to 0.9 and vertical coordinates negative 1.2 to 2.2 with no obvious pattern. Also, the following individual points are plotted: (1.9,2.2), (4.0,0.0), (4.3,2.2). All coordinates are approximate.
B.
-15-11Tear RatingPlate Gap
Edit Coordinates(0,0)
A scatter plot has a horizontal axis labeled Tear Rating from negative 1 to 5 to in increments of 1 and a vertical axis labeled Plate Gap from negative 1.25 to 1 in increments of 0.25. A series of plotted points range from horizontal coordinates 0.0 to 0.9 and vertical coordinates negative 1.2 to 0.5 with no obvious pattern. Also, the following individual points are plotted: (1.9,0.1), (4.0,0.6), (4.3,0.2). All coordinates are approximate.
C.
-11-15Plate GapTear Rating
Edit Coordinates(0,0)
A scatter plot has a horizontal axis labeled Plate Gap from negative 1.25 to 1 in increments of 0.25 and a vertical axis labeled Tear Rating from negative 1 to 5 to in increments of 1. A series of plotted points range from horizontal coordinates negative 1.2 to 0.5 and vertical coordinates 0.0 to 0.9 with no obvious pattern. Also, the following individual points are plotted: (0.1,1.9), (0.6,4.0), (0.2,4.3). All coordinates are approximate.
D.
-15-15Plate GapTear Rating
Edit Coordinates(0,0)
A scatter plot has a horizontal axis labeled Plate Gap from negative 2 to 5 in increments of 1 and a vertical axis labeled Tear Rating from negative 1 to 5 to in increments of 1. A series of plotted points range from horizontal coordinates negative 1.2 to 2.2 and vertical coordinates 0.0 to 0.9 with no obvious pattern. Also, the following individual points are plotted: (0.4,1.9), (negative 0.3,4.0), (2.2,4.3). All coordinates are approximate.b. Assuming a linear relationship, use the least-squares method to find the regression coefficients
b0
and
b1.
b0 |
equals= |
nothing |
b1 |
equals= |
nothing |
(Round to four decimal places as needed.) |
c. Interpret the meaning of the slope,
b1,
in this problem. Choose the correct answer below.
A.
For each increase of one in the tear rating, the plate gap is expected to increase by
b1
units.
B.
The approximate plate gap when the tear rating is 0 is
b1
units.
C.
The approximate tear rating when the plate gap is 0 units is
b1.
D.
For each one-unit increase in the plate gap, the tear rating is expected to increase by
b1.
d. Predict the mean tear rating when the plate gap is equal to 0.
nothing
(Round to four decimal places as needed.)
e. What should you tell management of the coffee company about the relationship between the plate gap and the tear rating?
A.
The tear rating is not affected by the plate gap.
B.
The tear rating is affected by the plate gap. As the plate gap increases, the tear rating
increasesincreases.
C.
As the plate gap increases, the tear rating
decreasesdecreases.
The tear rating is affected by the plate gap.
D.
As the tear rating increases, the plate gap decreases. The plate gap is affected by the tear rating.
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ANSWER:
EXPLANATION:
As per question given answer is below
Question a)
Answer: Option B
Question b)
We copy the data in excel. There we go to Data Analysis and select the Regression. We input the data for x and y and we get the regression output where we can find the b0 and b1 values.
SUMMARY OUTPUT |
||||||
Regression Statistics |
||||||
Multiple R |
0.549481 |
|||||
R Square |
0.301929 |
|||||
Adjusted R Square |
0.260866 |
|||||
Standard Error |
1.09878 |
|||||
Observations |
19 |
|||||
ANOVA |
||||||
df |
SS |
MS |
F |
Significance F |
||
Regression |
1 |
8.8772 |
8.8772 |
7.3528 |
0.0148 |
|
Residual |
17 |
20.5244 |
1.2073 |
|||
Total |
18 |
29.4016 |
||||
Coefficients |
Standard Error |
t Stat |
P-value |
Lower 95% |
Upper 95% |
|
Intercept |
1.0481 |
0.2696 |
3.8879 |
0.0012 |
0.4793 |
1.6169 |
X Variable 1 |
2.0100 |
0.7413 |
2.7116 |
0.0148 |
0.4461 |
3.5740 |
Answer:
bo= 1.0481
b1 = 2.0100
Question c)
Answer: Option A
Question d)
Answer: 1.0481
Question e)
Answer: Option B
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