37.0mL of NaOH is required to titrate 70.0mL of 0.155M H3A to the volume where pH=pKa2....

37.0mL of NaOH is required to titrate 70.0mL of 0.155M H₃A to the volume where pH=pKa₂. What is the molarity of the titrant?

Expert Solution

2NaOH + H3A ----------> Na2HA + 2H2O

2 moles 1 moles

NaOH H3A

M1 = M2 = 0.155M

V1 =37ml V2 = 70ml

n1 = 2 n2 = 1

M1V1/n1 = M2V2/n2

M1 = M2V2n1/V1n2

= 0.155*70*2/1*37 = 0.586M

queen_honey_blossom answered 2 years ago

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